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alisha [4.7K]
2 years ago
6

Pedro found a treasure map that said to take 12 steps north, then 8 steps south. Where is Steve in relationship to where he star

ted?
Mathematics
1 answer:
Tanzania [10]2 years ago
7 0
4 steps more north from where he started
I think
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The area of a rectangular wall of a barn is 32 square feet. It’s length is 4 feet longer than the width. Find the length and wid
Gnom [1K]

Answer:

Step-by-step explanation:

Givens

Area = L * w

w = x

l = x  + 4

Area = 32

Solution

32 = x(x + 4)

32 = x^2 + 4x

x^2 + 4x - 32

(x + 8)(x - 4)

Only x - 4 is going to make any sense

x - 4 = 0

x = 4

The width is 4

The length is 4 + 4 = 8

4*8 = 32 which is the area.

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3 years ago
Starting with some gold coins and some empty
Nezavi [6.7K]

Answer:

162

Step-by-step explanation:

5 0
2 years ago
Randall’s family drove to the beach for vacation. Assume they drove the same speed throughout the trip. The first day, they drov
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<span>Randall’s family drove to the beach for vacation. Assume they drove the same speed throughout the trip. The first day, they drove 130miles in 22 hours. The second day, they drove 325 miles in 55 hours. The third day, they arrived at the beach by driving 390 miles in 66 hours.</span>
7 0
3 years ago
Help ASAP thank you!! And show work !
RUDIKE [14]

Answer:

c. -2

Step-by-step explanation:

Since f(x) is the regular graph. Since the inverse function flips the x and y coordinates, f inverse of 4 is actually where y=4, not x=4. so the x coordinate where y is 4 is -2.

6 0
3 years ago
Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.
Leni [432]

Answer:

a)

g(2.9) \approx -6.6

g(3.1) \approx -3.4

b)

The values are too small since g'' is positive for both values of x in. I'm speaking of the x values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on that line.

We want to find the equation of the tangent line of the curve g at the point (3,-5) on g.

So we know (x_1,y_1)=(3,-5).

To find m, we must calculate the derivative of g at x=3:

m=g'(3)=(3)^2+7=9+7=16.

So the equation of the tangent line to curve g at (3,-5) is:

y-(-5)=16(x-3).

I'm going to solve this for y.

y-(-5)=16(x-3)

y+5=16(x-3)

Subtract 5 on both sides:

y=16(x-3)-5

What this means is for values x near x=3 is that:

g(x) \approx 16(x-3)-5.

Let's evaluate this approximation function for g(2.9).

g(2.9) \approx 16(2.9-3)-5

g(2.9) \approx 16(-.1)-5

g(2.9) \approx -1.6-5

g(2.9) \approx -6.6

Let's evaluate this approximation function for g(3.1).

g(3.1) \approx 16(3.1-3)-5

g(3.1) \approx 16(.1)-5

g(3.1) \approx 1.6-5

g(3.1) \approx -3.4

b) To determine if these are over approximations or under approximations I will require the second derivative.

If g'' is positive, then it leads to underestimation (since the curve is concave up at that number).

If g'' is negative, then it leads to overestimation (since the curve is concave down at that number).

g'(x)=x^2+7

g''(x)=2x+0

g''(x)=2x

2x is positive for x>0.

2x is negative for x.

That is, g''(2.9)>0 \text{ and } g''(3.1)>0.

So 2x is positive for both values of x which means that the values we found in part (a) are underestimations.

6 0
3 years ago
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