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3 years ago

11

What temp does paper burn at?

2 answers:

mafiozo [28]3 years ago

5 0

Answer:

paper ignites at around 480 degrees Fahrenheit, it gets far hotter once it's burning.

Step-by-step explanation:

The temperature at the center of a paper fire is 1,500 degrees Fahrenheit, give or take a couple hundred. The tips of the flames themselves are usually between 600 and 800 degrees..

zzz [600]3 years ago

4 0

Answer:

according to a website "A regular paper will ignite at 480-degree temperature".

Step-by-step explanation:

https://fireproofdepot.com/what-temperature-does-paper-burn/#:~:text=1%20A%20regular%20paper%20will%20ignite%20at%20480-degree,reach%20up%20to%201500%C2%B0F%20during%20the%20ignition%20time.

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Give the inequality -8<2 explain what happens when you multiply or divide both sides by 2 and what happens when you multiply

rodikova [14]

Answer:

If we multiply both the sides by 2, the inequality signs remains the same.

If we divide both sides by -2, the sign changes.

Step-by-step explanation:

The given inequality is

-8<2

If we multiply both the sides by 2, we get

-8 * 2 < 2*2

-16 < 4

The inequality signs remains the same.

On the other hand if we divide both sides by -2, we get -

-8/-2 < 2/-2

4 > -1

Here the sign changes.

4 0

3 years ago

16 X +12 over two equals 100

scoray [572]

The value of x in the given equation i.e $\frac{16x+12}{2}=100$ is 11.825

Given that equation $\frac{16x+12}{2}=100$ and asked to evaluate the value of x in the given equation

⇒ $\frac{16x+12}{2}=100$ (given equation)

To solve the given equation, need to use the various mathematical operations i.e division and subtraction)

⇒8x+6=100 ( using the operation division)

⇒8x=100-6 (using the operation subtraction)

⇒8x=94

⇒x= $\frac{94}{8}$ (using the operation division)

⇒x=11.825

By using the mathematical operations i.e division and subtraction the value of x came as 11.825

⇒Therefore, The value of x in the given equation i.e $\frac{16x+12}{2}=100$ is 11.825

Learn more about equation here:

brainly.com/question/10413253

#SPJ9

6 0

2 years ago

Please please ASAP ASAP please ASAP thank you so <br> No links or files

inessss [21]

Answer:

c

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Suppose that $p$ and $q$ are positive numbers for which \[\log_9 p = \log_{12} q = \log_{16} (p + q).\] what is the value of $q/

SVEN [57.7K]

Given $p,q>0$ and $\log_9p=\log_{12}q=\log_{16}(p+q)=x$ (say).

Then,

$p=9^x\\ q=12^x\\ p+q=16^x$

From the above 3 equations,

$\frac{q}{p} =(\frac{12}{9} )^x\\ \frac{q}{p} =(\frac{4}{3} )^x\\ \frac{p+q}{p} =(\frac{16}{9} )^x\\ \frac{p+q}{p} =(\frac{4}{3} )^{2x}\\$

From the equations, we get

$\frac{p+q}{p}=(\frac{q}{p})^2\\ 1+\frac{q}{p}=(\frac{q}{p})^2\\ (\frac{q}{p})^2-\frac{q}{p}-1=0\\ \frac{q}{p}=\frac{1 \pm \sqrt{5}}{2}$

Since $p,q>0$ , the negative value is rejected.

$\frac{q}{p}=\frac{1 + \sqrt{5}}{2}$

3 0

4 years ago

What is the weight difference??

Nana76 [90]

Answer:

32 lbs

Step-by-step explanation:

John weighs 104 lbs

Rita weighs 136 lbs

The difference is 136-104 = 32 lbs

7 0

3 years ago