Given:
A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5.
To find:
The coordinates of that point.
Solution:
Section formula: If point divides a line segment in m:n, then the coordinates of that point are
A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5. Using section formula, we get
Therefore, the coordinates of the required point are (0,3).
You can arrange it any way as long as you keep the 2 as the very first number
X=-2y-3/2 idk what else to type
Answer:
The answer is A.
Step-by-step explanation:
Keeping point y as a reference, we know that it was rotated 180 degrees around the origin. I could tell this because y moved from one corner to another, if it was rotated 90 degrees it would move in a different direction. We also know it moved clockwise because if it moved counter clockwise it would have a different location.
We also know that it was shifted across the x-axis because it moved to the right. If it moved downwards it would have moved in the y direction.
Hope this helps.
Answer:
<h2>(k ∘ p)(x) = 2x² - 16x + 25</h2>
Step-by-step explanation:
k(x) = 2x² - 7
p(x) = x - 4
To find (k ∘ p)(x) substitute p(x) into k(x),
that's replace any x in k(x) by p(x)
We have
(k ∘ p)(x) = 2(x - 4)² - 7
Expand
(k ∘ p)(x) = 2( x² - 8x + 16) - 7
= 2x² - 16x + 32 - 7
Simplify
We have the final answer as
<h3>(k ∘ p)(x) = 2x² - 16x + 25</h3>
Hope this helps you
