"A day care program has an average daily expense of $75.00. The standard deviation is $5.00. The owner takes a sample of 64 bill
s. What is the probability the mean of his sample will be between $70.00 and $80.00?"
2 answers:
Answer:
p=1
Step-by-step explanation:
Given that a day care program has an average daily expense of $75.00. The standard deviation is $5.00.
Sample size = 64
Std error of sample = 
Thus sample mean will follow normal with
(75, 0.625)
Required probability
=
It is almost a certain event with p =1
Answer:
their you go i had it wrong so thought i give someone the right answer
Step-by-step explanation:
1.0
34
1.0
34
68
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c. 5
Step-by-step explanation:
1.5m = 1.5*100 cm = 150 cm
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Answer: t = -93
Step-by-step explanation:
64= -8(t+85)
64= -8t - 680
744= -8t
93= -t
93= t
Step-by-step explanation:
without seeing a picture I'm guessing 45 45, and 90
