Question

"A day care program has an average daily expense of $75.00. The standard deviation is $5.00. The owner takes a sample of 64 bills. What is the probability the mean of his sample will be between $70.00 and $80.00?"

Answer 1

Answer:

p=1

Step-by-step explanation:

Given that a day care program has an average daily expense of $75.00. The standard deviation is $5.00.

Sample size = 64

Std error of sample = $\frac{5}{\sqrt{64} } \\=0.625$

Thus sample mean will follow normal with

(75, 0.625)

Required probability

=$P(70$

It is almost a certain event with p =1

Answer 2

Answer:

their you go i had it wrong so thought i give someone the right answer

Step-by-step explanation:

1.0

34

1.0

34

68