Please help me with this 4 question

Mathematics

2 answers:

Dennis_Churaev [7]1 year ago

6 0

Answer:

Step-by-step explanation:

Volume in math means s the amount of space in a 3D object.

the formula is l × W × H

So you do 25 × 11.25 × 6

it equals to 1687.5.

Therefore, the volume of the brick is 1687.5

NARA [144]1 year ago

4 0

Answer:

i) c. 1,08,00,000 cm³

ii) c. 1687.5 cm³

iii) b. 6400

Q.3) Suface area of cube is 294 cm².

Step-by-step explanation:

Q.2. 12 men are building a wall which is 8 m long, 6 m high and 22.5 cm thick using bricks. On this basis answer the following.

i. Find the volume of the cuboidal wall.

Length (l) = 800 m
Breadth (b) = 6600 m
Height (h) = 22.5 cm

Substituting all the given values in the formula to find volume of cuboidal wall :

$\begin{gathered}\qquad{\longrightarrow{\sf{V = LBH}}} \\ \\ \qquad{\longrightarrow{\sf{V = L \times B \times H}}} \\ \\ \qquad{\longrightarrow{\sf{V = 800 \times 600 \times 22.5}}} \\ \\ \qquad{\longrightarrow{\sf{V = 480000 \times 22.5}}} \\ \\ \qquad{\longrightarrow{\sf{\underline{\underline{\red{V = 1,08,00,000 \: {cm}^{3}}}}}}} \end{gathered}$

Hence, the volume of cuboidal wall is 1,08,00,000 cm³.

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ii. If the dimension of each brick is 25 cm × 11.25 cm × 6 cm, then find the volume of the brick.

Length (l) = 25 cm
Breadth (b) = 11.25 m
Height (h) = 6 cm

Substituting all the given values in the formula to find the volume of cuboidal brick :

$\begin{gathered}\qquad{\longrightarrow{\sf{V = LBH}}} \\ \\ \qquad{\longrightarrow{\sf{V = L \times B \times H}}} \\ \\ \qquad{\longrightarrow{\sf{V = 25 \times 11.25\times 6}}} \\ \\ \qquad{\longrightarrow{\sf{V = 281.25\times 6}}} \\ \\ \qquad{\longrightarrow{\sf{\underline{\underline{\pink{V = 1687.5 \: {cm}^{3}}}}}}} \end{gathered}$

Hence, the volume of cuboidal brick is 1687.5 cm³.

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iii. How many bricks will be required to construct the cuboidal wall.

Volume of wall = 10800000 cm³
Volume of brick = 1687.5 cm³

Substituting all the given values in the formula to find the number of bricks :

$\begin{gathered} \quad{\longrightarrow{\sf{No. \: of \: bricks = \dfrac{Volume \:of \: wall}{Volume \: of \: brick}}}}\\ \\ \quad{\longrightarrow\sf{No.\: of \: bricks = \dfrac{10800000}{1687.5}}} \\ \\ \quad{\longrightarrow{\sf{No. \: of \: bricks = \cancel{\dfrac{10800000}{1687.5}}}}} \\ \\ \quad{\longrightarrow{\sf{\underline{\underline{\purple{No. \: of \: bricks = 6400}}}}}}\end{gathered}$