The formula for the mass in terms of angular velocity and spring constant is m = ω²/k
Given the expression as:
ω = √km
Given that
ω is the angular velocity
m is the mass suspended from a spring
k is the spring constant
Making m the subject of the formula
Step 1: Take the square of both sides
ω² = (√km)²
ω² = km
Step 2: Divide both sides by k
ω²/k = km/k
ω²/k = m
Swap
m = ω²/k
Hence the formula for the mass in terms of angular velocity and spring constant is m = ω²/k
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Diameter = 2.5 ft
Radius =

a) The Circumference formula of a circle is given in the picture below, we can plug-in the given information
C = 2

(1.25) or 2.5
≈ 7.85 ft (we can leave the answer in terms of pi {

})
b) We divide the total number of distance the tire will travel by the circumference to find how many times the tire will roll
(I have used the value in feet because we found the circumference in feet units and notice that I took the value of circumference to be 2.5

instead of 7.85, to increase accuracy)
672.2
The tire will rotate
672 times (a tire cannot roll a decimal times, so we take to the nearest whole number) to travel 1 mile
Plug in n = 5 to find the 5th term
T(5) = 2(5) - 7
T(5) = 10 - 7
T(5) = 3
The 5th term is 3.
Answer:
x = 8 y = 2
(8,2)
Step-by-step explanation:
You have to find the value of both x and y
x + 4y = 8
to find x you have to cancel out y so,
x + 4(0) = 8
x = 8
to find y you have to cancel out x
0 + 4y = 8
4y = 8
divide both sides by 4
y = 2
Hope this Helps!!!