Answer:
0.017559
Step-by-step explanation:
Data provided:
Probability of Households Having cable TV, p₀ = 76% = 0.76
Therefore,
The probability that the Households not having cable TV = 1 - 0.76 = 0.24
Sample size, n = 225 households
sample proportions is less than 82% i.e p = 0.82
Now,
The standard error, SE = 
or
SE = 
or
SE = 0.02847
and,
or
or
Z = 2.107
therefore,
P(sample porportions < 0.82) = P(Z < 2.107)
now from the p value from the Z table
we get
P(sample porportions < 0.82) = 0.017559
Answer:
you got 12 more then your friend, 45-23
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
since coefficient of x = 0
Answer:
All numbers can be written as a product of the prime numbers that conform them.
A) Find two numbers with a common factor of 3 only.
for example:
2*3 = 6
7*3 = 21
Both numbers have the factor 3 in them, and because the other two numbers are primes, we can be sure that the 3 is the only common factor.
B) Write a pair of numbers with a common factor of 2, 3 and 6.
Here we can write:
2*3*2 = 12
3*2*5 = 30
Those two numbers have the common factors 6, 2 and 3.
C) Write a pair of numbers with common factors of 3, 6 and 9.
3*2*3 = 18 (has the factors 2, 3, 3*2 = 6, 3*3 = 9)
-3*2*6 = -36
Both have the common factors 3, 6 and 9 (and they share more common factors like 2, this happens because 6 = 3*2, so if 6 is a common factor, 2 also must be)
Given :
Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more tickets were sold to students than to teachers. 904 tickets were sold to parents.
To Find :
How many tickets were sold to students.
Solution :
Ticket sold to teachers, T = 563 .
Ticket sold to parents, P = 904 .
Let, ticket sold to students are S.
Now, it is given that :
S = T + 904
S = 563 + 904
S = 1467 students
Therefore, tickets sold to students are 1467 .
Hence, this is the required solution.
