Question

An object is orbiting uniformly around a center, has a radius of 1 km, and undergoes an angular displacement of 1 every 0.1 s. What is the position vector (x and y component) of that object at = 1 s if the object starts its motion at x = 1000m, y = 0 m?

Answer 1

The position vector of the object after 1 second is (11,000 m, 10,000 m).

Angular speed of the object

The angular speed of the object is calculated as follows;

$\omega = \frac{1 \ }{0.1 \ s} = 10 \ rad/s$

Linear speed of the object

v = ωr

v = 10 x 1 km

v = 10 x 1000 m

v = 10,000 m/s

Position of the object after 1 second

$v_x = 1000\ m \ + \ 10,000\ m/s \times 1\ s = 11,000 \ m\\\\v_y = 0 m \ + \ 10,000 \ m/s \times 1 \ s = 10,000 \ m$

Learn more about angular speed here: brainly.com/question/6860269