<span>The combined
gas law has no official founder; it is simply the incorporation of the three
laws that was discovered. The combined gas law is a gas law that combines
Gay-Lussac’s Law, Boyle’s Law and Charle’s Law.
Boyle’s law states that pressure is inversely proportional with volume
at constant temperature. Charle’s law states that volume is directly
proportional with temperature at constant pressure. And Gay-Lussac’s law shows
that pressure is directly proportional with temperature at constant volume. The
combination of these laws known now as combined gas law gives the ratio between
the product of pressure-volume and the temperature of the system is constant.
Which gives PV/T=k(constant). When comparing a substance under different
conditions, the combined gas law becomes P1V1/T1 = P2V2/T2.</span>
Rubber. The other three are metals, and therefore good conductors.
When the same masses are heated by the same amount copper will heat up the fastest. Copper is a good conductor of heat that is why it easily heats up. Gold is not a good conductor of heat because of its stable properties.
Every piece of matter begins “Out of this world”
Question:
A 63.0 kg sprinter starts a race with an acceleration of 4.20m/s square. What is the net external force on him? If the sprinter from the previous problem accelerates at that rate for 20m, and then maintains that velocity for the remainder for the 100-m dash, what will be his time for the race?
Answer:
Time for the race will be t = 9.26 s
Explanation:
Given data:
As the sprinter starts the race so initial velocity = v₁ = 0
Distance = s₁ = 20 m
Acceleration = a = 4.20 ms⁻²
Distance = s₂ = 100 m
We first need to find the final velocity (v₂) of sprinter at the end of the first 20 meters.
Using 3rd equation of motion
(v₂)² - (v₁)² = 2as₁ = 2(4.2)(20)
v₂ = 12.96 ms⁻¹
Time for 20 m distance = t₁ = (v₂ - v ₁)/a
t₁ = 12.96/4.2 = 3.09 s
He ran the rest of the race at this velocity (12.96 m/s). Since has had already covered 20 meters, he has to cover 80 meters more to complete the 100 meter dash. So the time required to cover the 80 meters will be
Time for 100 m distance = t₂ = s₂/v₂
t₂ = 80/12.96 = 6.17 s
Total time = T = t₁ + t₂ = 3.09 + 6.17 = 9.26 s
T = 9.26 s
