1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Karolina [17]
3 years ago
7

Need help!!! A charge of 8.5 × 10–6 C is in an electric field that has a strength of 3.2 × 105 N/C. What is the electric force a

cting on the charge?
A. 0.27 N
B. 2.7 N
C. 27 N
D. 270 N
Physics
2 answers:
Papessa [141]3 years ago
4 0

Answer:

Electric force, F = 2.7 N

Explanation:

It is given that,

Magnitude of electric charge, q=8.5\times 10^{-6}\ C

Electric field, E=3.2\times 10^{5}\ N/C

We have to find the electric force acting on the charge. It is given by the product of electric charge and electric field i.e.

F=q\times E

F=8.5\times 10^{-6}\times 3.2\times 10^{5}

F = 2.72 N

Hence, the correct option is (b) " 2.7 N"

ddd [48]3 years ago
3 0
B is the right answer. Multiply numbers you get the answer
You might be interested in
Which Richter magnitude range can be recorded by instruments but isn't felt? A. less than 2.9 B. 3.0 – 4.9 C. 5.0 – 5.9 D. 6.0 a
algol [13]

A. anything less than 3.0 magnitude on a richters scale usually can't be felt by humans but instruments can pick it up.

3 0
3 years ago
Read 2 more answers
What is 300N divided by 25 kg?
snow_lady [41]

Answer:

Explanation:

it is acceleration because we know that

F=ma

a=F/m

a=300N/25 kg

a=12 m/s^2

3 0
3 years ago
What are close-toed shoes least likely to provide protection against?
Dennis_Churaev [7]
Hydrogen gas is harmless to your feet so since you don’t need protection against it that seems the best answer.
8 0
3 years ago
Read 2 more answers
Consider a 2.54-cm-diameter power line for which the potential difference from the ground, 19.6 m below, to the power line is 11
tiny-mole [99]

Answer:

The line charge density is 1.59\times10^{-4}\ C/m

Explanation:

Given that,

Diameter = 2.54 cm

Distance = 19.6 m

Potential difference = 115 kV

We need to calculate the line charge density

Using formula of potential difference

V=EA

V=\dfrac{\lambda}{2\pi\epsilon_{0}r}\times\pi r^2

\lambda=\dfrac{V\times2\epsilon_{0}}{r}

Where, r = radius

V = potential difference

Put the value into the formula

\lambda=\dfrac{115\times10^{3}\times2\times8.8\times10^{-12}}{1.27\times10^{-2}}

\lambda=1.59\times10^{-4}\ C/m

Hence, The line charge density is 1.59\times10^{-4}\ C/m

4 0
3 years ago
How does the angle of launch affect the kinetic energy of a rubber band?​
Lady_Fox [76]

Answer:

The angle of launch of the rubber band affects the initial velocity. The more the rubber band is stretched the more force it applies to return to equilibrium and the more kinetic energy that results in.

3 0
3 years ago
Other questions:
  • What is used in an electrical circuit to prevent a short circuit?
    10·1 answer
  • Can neutrons be accelerated in a cyclotron?Give reason.
    9·1 answer
  • A 1,200 kg car rolls down a hill with its brakes off and transmission in neutral. At one moment it is moving 5.0 m/s. A little l
    7·1 answer
  • A 5.7 kg block attached to a spring executes simple harmonic motion on a frictionless horizontal surface. At time t = 0s, the bl
    11·1 answer
  • How does an inclined plane work? A A small input force is exerted over a long distance. B A large output force is exerted over a
    7·1 answer
  • What branch of science does anatomy fall under?
    11·1 answer
  • Which change will always result in an increase in the gravitational force between two objects?
    8·1 answer
  • 3) A school bus traveling at 12 m/s has a momentum of 144,000 kg.m/s.
    6·2 answers
  • . A 225-kg crate is pushed horizontally with a force of 710 N. If the coefficient of friction is 0.20, calculate the acceleratio
    12·1 answer
  • PLEASE HELP ASAPP!!!
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!