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GREYUIT [131]
3 years ago
7

What is the circumference of the circle? (use 3.14 for pi)

Mathematics
1 answer:
Vinvika [58]3 years ago
8 0

Answer:

94.2 is my best guess

Step-by-step explanation:

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Hi, help a sis out please :( thank you!!
maksim [4K]

Answer:

Yeah, D is the right anwser!

Step-by-step explanation:

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7 0
3 years ago
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What is the value of f(x) = 2(0.75)^x when x=3
Nadusha1986 [10]
<span>f(x) = 2(0.75)^x 
at x = 3
>> </span>f(3) = 2(0.75)^3 
>> f(3) = <u>0.84375</u>
6 0
4 years ago
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WHAT IS THE SUM OF 76/81 X 80/76
Advocard [28]

Answer:

80/81

Step-by-step explanation:

hope this helps!

6 0
3 years ago
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A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0
oksian1 [2.3K]
<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

\overline{x}\pm z^* SE                   (1)

, where \overline{x} = sample mean

z* = critical value.

SE = standard error

and SE=\dfrac{\sigma}{\sqrt{n}} , \sigma = population standard deviation.

n= sample size.

As per given , we have

\overline{x}=74.021

\sigma=0.001

n= 15

It is known that ring diameter is normally distributed.

SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

74.021\pm (2.576) (0.000258199)     (using (1))

74.021\pm 0.000665120624

74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)  [Rounded to three decimal places]

∴  A 99% two-sided confidence interval on the true mean piston diameter  = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

74.021- (1.96) (0.000258199)    (using (1))

74.021- 0.00050607004=74.02049393\approx74.020 [Rounded to three decimal places]

∴  A 95% lower confidence bound on the true mean piston diameter= 74.020

7 0
3 years ago
4) During a school carnival, students from the middle school raised money by selling crafts, food, game tickets, and school play
ioda

$225 was earned from the craft sales

and $40 was earned from the play.

Given, During a school carnival, students from the middle school raised money by selling crafts, food, game tickets, and school play admissions.

Of each dollar earned, $0.15 came from games. Craft sales earned 3 times as much as games. Food sales were 4 times the amount earned from the play.

Let the amount earned by play be x,

Now, Games earned = 0.15×500 = $75

Also, crafts earned 3×75 = $225

Now, as play earned x, then food earned 4x.

According to question,

x + 75 + 225 + 4x = 500

5x + 300 = 500

5x = 200

x = 40

So, the amount earned by Play be, $40

and the amount earned by Food be $160.

Hence, $225 was earned from the craft sales

and $40 was earned from the play.

Learn more about Linear Equations here brainly.com/question/24085666

#SPJ1

5 0
1 year ago
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