Working out required, help asap, please! <3

A number is between 50 and 55. It has prime factors of 2, and 9. What is the number?

mihalych1998 [28]

Answer:

The answer is 54.

Step-by-step explanation:

54 divided by 2 will give you 27.

54 divided by 9 will give you 6.

3 0

3 years ago

If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$

Now we have everything in order to replace into formula (1):

$62-2.72\frac{8}{\sqrt{36}}=58.373$

$62+2.72\frac{8}{\sqrt{36}}=65.627$

So on this case the 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0

4 years ago

Anyone know this? Sorry if the image is bad.

PilotLPTM [1.2K]

The answer is B). graph B

8 0

3 years ago

To the nearest tenth, what is the length in units of MN?

melisa1 [442]

Answer:

10

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Sue initially has 5 hours of pop music and 4 hours of classical music in her collection. Every month onwards, the hours of pop m

Snezhnost [94]

<h2>Answer</h2>

f(x) = 5(1.25)x + 4

<h2>Explanation</h2>

To solve this, we are going to use the standard exponential equation:

$f(x)=a(1+b)^x$

where

$a$ is the initial amount

$b$ is the growth rate in decimal form

$x$ is the time (in months for our case)

Since the hours of classic music remain constant, we just need to add them at the end. We know form our problem that Sue initially has 5 hours of pop, so $a=5$ ; we also know that every month onward, the hours of pop music in her collection is 25% more than what she had the previous month, so $b=\frac{25}{100} =0.25$ . Now let's replace the values in our function:

$f(x)=a(1+b)^x$

$f(x)=5(1+0.25)^x$

$f(x)=5(1.25)^x$

Now we can add the hours of classical music to complete our function:

$f(x)=5(1.25)^x+5$

6 0

3 years ago

Read 2 more answers