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3 years ago

5

The weight of an object on a particular scale is 142.2 lbs the measured weight may vary from the actual weight by at most 0.3 lb

s. what is the range of actual weights of the object

1 answer:

algol133 years ago

3 0

Answer:

144.9 <= x <= 145.5

Step-by-step explanation:

145.2 + 3 = 145.5

145.2 - 3 = 144.9

144.9 <= x <= 145.5

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Point W(-6, 7) is rotated 90° clockwise. Where is W'?

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You are out bottle caps, and decide to use Popsicle sticks instead. You measure them, and they are 15.2 cm tall. How many Popsic

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The price of a gallon number 2 fuel oil went from 0.64 to 0.68 per gallon what was the percent of increase in the price of a gal

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3 years ago

A 160-inch strip of metal 20 inches wide is to be made into a small open trough by bending up two sides on the long side, at rig

babymother [125]

Answer:

The value of double derivative at x=4.834 is negative, therefore the trough have a maximum volume at x=4.834 inches.

Step-by-step explanation:

The dimensions of given metal strip are

Length = 160 inch

Width = 20 inch

Let the side bend x inch from each sides to make a open box.

Dimensions of the box are

Length = 160-2x inch

Breadth = 20-2x inch

Height = x inch

The volume of a cuboid is

$V=length\times breadth \times height$

Volume of box is

$V(x)=(160-2x)\times (20-2x)\times x$

$V(x)=(160-2x)(20-2x)x$

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Equate V'(x)=0, to find the critical points.

$0=12x^2 - 720 x + 3200$

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$x=30\pm 10\sqrt{\frac{\left(19\right)}{3}}$

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Differentiate V'(x) with respect to x.

$V'(x)=24x - 720$

The value of double derivative at critical points are

$V'(55.166)=24(55.166) - 720=603.984$

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Since the value of double derivative at x=4.834 is negative, therefore the trough have a maximum volume at x=4.834 inches.

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3 years ago

Read 2 more answers

How many triangles exist with the side lengths of 7 7 7?

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Isn't there only one with sides that are all 7 units long?
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hit the brainiest button

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