So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
A = 2.25 (3.14)
A = 7.065 square inches.
Next, we deduct the area of circle from area of square and the result would be 1.935 <span>in². So the answer for this would be option B.
Hope this answer helps.</span>
Answer: <B is congruent to <E
Step-by-step explanation:
There is no “angle,angle,angle” theorem when proving triangles are congruent.
There are 5 however that do:
ASA (angle, included side, angle)
SSS (side, side, side)
SAS (side, included angle, side)
AAS (angle,angle, non included side)
HL (hypotenuse,leg)
Answer:
I Think Its C
Sorry if its wrong. Hope it helps...
Answer:
thats easy
Step-by-step explanation:
but thanks 4 the points
Answer:
300
Step-by-step explanation:
I t is good
