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Eddi Din [679]
3 years ago
10

Which number is between pi ans the square root of 14 ​

Mathematics
1 answer:
Katena32 [7]3 years ago
4 0

Answer:

3.5

Step-by-step explanation:

pi = 3.14159...

sqrt(14) = 3.74165...

The choices are: 1.5, 2.5, 3.5, 4.5

Of the four choices, the only one between 3.14... and 3.74... is 3.5.

Answer: 3.5

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Yuri [45]

Answer:

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Step-by-step explanation:

if you could give me a brainliest.

5 0
2 years ago
A certain new type of business succeeds 60% of the time. Suppose that 3 such businesses open (where they do not compete with eac
ella [17]

Answer:

0.216

Step-by-step explanation:

Given that a certain new type of business succeeds 60% of the time.

3 such businesses   are tested for success.

Since these three businesses open (where they do not compete with each other, so it is reasonable to believe that their relative successes would be independent). we can say X no of successful businesses is Binomial

with p = 0.6 and n =3

Required probability

=The probability that all 3 businesses succeed is:

= P(X=3)\\= 0.6^3\\= 0.216

8 0
3 years ago
Dont guess!<br> I will mark brainliest if its correct!<br> Also no links!
brilliants [131]

Answer:

I know you said no guessing, but I'm assuming it's the first one, F.

8 0
2 years ago
Read 2 more answers
31/8 as a mixed number?
Katyanochek1 [597]
\frac{31}{8}=\frac{24}{8}+\frac{7}{8}=3+\frac{7}{8}=\boxed{3 \frac{7}{8}}
5 0
3 years ago
Read 2 more answers
How to find average value of a function over a given interval?
Strike441 [17]
<span><span>f<span>(x)</span>=8x−6</span><span>f<span>(x)</span>=8x-6</span></span> , <span><span>[0,3]</span><span>[0,3]

</span></span>The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.<span><span>(−∞,∞)</span><span>(-∞,∞)</span></span><span><span>{x|x∈R}</span><span>{x|x∈ℝ}</span></span><span><span>f<span>(x)</span></span><span>f<span>(x)</span></span></span> is continuous on <span><span>[0,3]</span><span>[0,3]</span></span>.<span><span>f<span>(x)</span></span><span>f<span>(x)</span></span></span> is continuousThe average value of function <span>ff</span> over the interval <span><span>[a,b]</span><span>[a,b]</span></span> is defined as <span><span>A<span>(x)</span>=<span>1<span>b−a</span></span><span>∫<span>ba</span></span>f<span>(x)</span>dx</span><span>A<span>(x)</span>=<span>1<span>b-a</span></span><span>∫ab</span>f<span>(x)</span>dx</span></span>.<span><span>A<span>(x)</span>=<span>1<span>b−a</span></span><span>∫<span>ba</span></span>f<span>(x)</span>dx</span><span>A<span>(x)</span>=<span>1<span>b-a</span></span><span>∫ab</span>f<span>(x)</span>dx</span></span>Substitute the actual values into the formula for the average value of a function.<span><span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(<span>∫<span>30</span></span>8x−6dx)</span></span><span>A<span>(x)</span>=<span>1<span>3-0</span></span><span>(<span>∫03</span>8x-6dx)</span></span></span>Since integration is linear, the integral of <span><span>8x−6</span><span>8x-6</span></span> with respect to <span>xx</span> is <span><span><span>∫<span>30</span></span>8xdx+<span>∫<span>30</span></span>−6dx</span><span><span>∫03</span>8xdx+<span>∫03</span>-6dx</span></span>.<span><span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(<span>∫<span>30</span></span>8xdx+<span>∫<span>30</span></span>−6dx)</span></span><span>A<span>(x)</span>=<span>1<span>3-0</span></span><span>(<span>∫03</span>8xdx+<span>∫03</span>-6dx)</span></span></span>Since <span>88</span> is constant with respect to <span>xx</span>, the integral of <span><span>8x</span><span>8x</span></span> with respect to <span>xx</span> is <span><span>8<span>∫<span>30</span></span>xdx</span><span>8<span>∫03</span>xdx</span></span>.<span><span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(8<span>∫<span>30</span></span>xdx+<span>∫<span>30</span></span>−6dx)</span></span><span>A<span>(x)</span>=<span>1<span>3-0</span></span><span>(8<span>∫03</span>xdx+<span>∫03</span>-6dx)</span></span></span>By the Power Rule, the integral of <span>xx</span> with respect to <span>xx</span> is <span><span><span>12</span><span>x2</span></span><span><span>12</span><span>x2</span></span></span>.<span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(8<span>(<span><span>12</span><span>x2</span><span>]<span>30</span></span></span>)</span>+<span>∫<span>30</span></span>−6dx<span>)</span></span></span>
3 0
3 years ago
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