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kiruha [24]
2 years ago
15

Please help I need some guidance.

Mathematics
2 answers:
melomori [17]2 years ago
6 0

Answer:

3/1000

Step-by-step explanation:

3 millimeters = 0.003 meters

So to get to 1 meter from 3 millimeters, you will have to divide by 0.003 or 3/1000 therefore the scale factor is 3/1000

Rzqust [24]2 years ago
5 0

Answer:

1/333 is answer........

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Complete the missing value in the solution to the equation.<br> y=-2x+4<br> y=-2
anygoal [31]

Answer:

X=3,y=-2

Step-by-step explanation:

This is a simultaneous equation question and we will have to solve using substitution method

So let's solve

y=-2x+4...(1)

y=-2....(2)

Let's substitute (2) into (1)

-2=-2x+4

Substrate 4 from both sides

-6=-2x

Divide both sides by-2

x=3

Substitute the value of x in (1)

y=-2(3)+4

y=-6+4

y=-2

Therefore x is 3,y is -2

3 0
2 years ago
What is the least common multiple of 2 and 9
harina [27]

Answer:

18

hope this helps

5 0
3 years ago
Read 2 more answers
Among cases of heart pacemaker malfunctions, were found to be caused by firmware, which is software programmed into the device.
alex41 [277]

Complete question is;

Among 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware, which is software programmed into the device. If the firmware is tested in three different pacemakers randomly selected from this batch of 8834 and the entire batch is accepted if there are no failures, what is the probability that the firmware in the entire batch will be accepted? Is this procedure likely to result in the entire batch being accepted?

Answer:

P(All three are not caused by firmware) = 83.84%

Probability that the entire batch will be accepted = 0.8384

Step-by-step explanation:

We are told that out of the 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware.

Thus,

Cases not caused by firmware = 8834 - 504 = 8330

So, probability of the first case not being affected by firmware is;

P(first case not caused by firmware) = 8330/8834

Also,

Probability of second case not being affected by firmware is given as;

P(second case not caused by firmware|first case not affected by firmware) = 8329/8833

Similarly,

Probability of third case not being affected by firmware is given as;

P(third case not caused by firmware|first and second not caused by firmware) = 8328/8832

Now, looking at the 3 Probabilities gotten, it is obvious that the events are not independent because the probability of occurence of one event depends on the probability of occurence of the other event.

Thus, we will make use of the general multiplication rule which is;

P(A & B) = P(B) × P(A|B)

Thus;

P(All three not caused by firmware) = P(first case not caused by firmware) × P(second case not caused by firmware|first case not affected by firmware) × P(third case not caused by firmware|first and second not caused by firmware)

Plugging in the relevant values, we have;

P(All three not caused by firmware) = (8330/8834) × (8329/8833) × (8328/8832)

P(All three are not caused by firmware) = 0.83840506679 ≈ 83.84%

6 0
3 years ago
What is the formula to find the the perimeter of 4 sided shape
yaroslaw [1]

Answer:

add all the sides together

a+b+c+d

4 0
2 years ago
Please help i need
Anon25 [30]

The measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.

<h3>what is measure centre and measure of variation? </h3>

A measure of central tendency (measure of centre) is a value that attempts to describe a set of data by identifying the central position of the data set.

The measure of central tendency includes the mean, median and mode.

The measure of variation describes the amount of variability or spread in a set of data.

The common  measures of variability are the range, the interquartile range (IQR), variance, and standard deviation.

Therefore, the measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.

learn more on measure of centre and variation here: brainly.com/question/23769503

#SPJ1

7 0
2 years ago
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