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Readme [11.4K]
3 years ago
15

What is the area of this irregular shape 28in 7in 20in 30in 25in

Mathematics
1 answer:
Alex777 [14]3 years ago
7 0

Answer:

b1=1b2=1h=7b1=1b2=6h=2b1=6b2=9h=2

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Write a literal corresponding to the floating point value one-and-a-half.
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<span>1.5 In C or C++, a floating point literal is nothing more than a sequence of decimal digits with either or both an decimal point, or an exponent with optionally a type specifier. The value could be any of the following: 1.5, 1.5e0, 0.15e1, 15e-1, etc.</span>
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3 years ago
I’m very confused so can someone help me with this math problem please.
GenaCL600 [577]

Answer:

244

Step-by-step explanation:

34
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5 0
3 years ago
Please help I'm desperate :(
zubka84 [21]

Answer:

x=5

Step-by-step explanation:

<u>Similar Triangles</u>

By looking at the construction of the figure, we can safely assume both triangles are similar, i.e. their internal angles are equal and their sides are proportional. Following the proportion of the heights and bases of both triangles we can set this relationship:

\displaystyle \frac{45}{36}=\frac{5x}{20}

Simplifying both fractions

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Solving for x

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8 0
3 years ago
The drama club is showing a video of their recent play.The first showing will begin at 2:30pm.The second showing was scheduled t
Rudiy27
The second showing had begun at 5:25. And there had been a 1/2 hour (30 minutes) break before it. So we substract this break from 5:25 and we get 4:55 - the time when the first showing had ended. 

So the first showing had begun at 2:30 and had ended at 4:55. By substracting 2:30 from 4:55 we get 2:25 - that's the duration of the video.

The answer is 2 hours and 25 minutes.
4 0
3 years ago
Read 2 more answers
A positive integer from one to six is to be chosen by casting a die. Thus the elements c of the sample space C are 1, 2, 3, 4, 5
Alex_Xolod [135]

Answer with Step-by-step explanation:

We are given that six integers 1,2,3,4,5 and 6.

We are given that sample space

C={1,2,3,4,5,6}

Probability of each element=\frac{1}{6}

We have to find that P(C_1),P(C_2),P(C_1\cap C_2) \;and\; P(C_1\cup C_2)

Total number of elements=6

C_1={1,2,3,4}

Number of elements in C_1=4

P(E)=\frac{number\;of\;favorable \;cases}{Total;number \;of\;cases}

Using the formula

P(C_1)=\frac{4}{6}=\frac{2}{3}

C_2={3,4,5,6}

Number of elements in C_2=4

P(C_2)=\frac{4}{6}=\frac{2}{3}

C_1\cap C_2={3,4}

Number of elements in (C_1\cap C_2)=2

P(C_1\cap C_2)=\frac{2}{6}=\frac{1}{3}

C_1\cup C_2={1,2,3,4,5,6}

P(C_1\cup C_2)=\frac{6}{6}=1

4 0
3 years ago
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