9. 12 edges
Work: <u>4</u> horizontal edges on top, <u>4</u> horizontal edges on bottom, <u>4</u> vertical edges for sides
10. Ten-thousands place
Work: The 8 is highlighted. The order of places is: <u>ten-thousands</u>, thousands, hundreds, tens, ones
11. 10 4/5
Work: 54 ÷ 5 ——> 50÷5 = <u>10</u> with 4 left over and put into a fraction of <u>4/5</u>
12. 3,000
Work: 2 is in the thousands place so you look to the place behind it and there is an 8. If the number behind is 5 through 9 then you round up. 8 is above 5, therefore, you round the 2 up to a <u>3</u>.
13. 0.45
Work: The pattern is +0.03 so 0.42+0.03=<u>0.45</u>
14. 54 cakes
Work: <u>6 eggs</u> per 1 cake • <u>9 cakes</u> = 6•9=54 eggs used
15. 378 desks in the school
Work: 6 rows • 7 desks per row = 42 desks in 1 classroom. 42 desks • 9 classrooms = 378 desks in the whole school
Answer:
Let v(t) be the velocity of the car t hours after 2:00 PM. Then 
. By the Mean Value Theorem, there is a number c such that 
with 
. Since v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 
.
Step-by-step explanation:
The Mean Value Theorem says,
Let be a function that satisfies the following hypotheses:
- f is continuous on the closed interval [a, b].
- f is differentiable on the open interval (a, b).
Then there is a number c in (a, b) such that
Note that the Mean Value Theorem doesn’t tell us what c is. It only tells us that there is at least one number c that will satisfy the conclusion of the theorem.
By assumption, the car’s speed is continuous and differentiable everywhere. This means we can apply the Mean Value Theorem.
Let v(t) be the velocity of the car t hours after 2:00 PM. Then 
and 
(note that 20 minutes is 
of an hour), so the average rate of change of v on the interval ![[0 \:h, \frac{1}{3} \:h]](https://tex.z-dn.net/?f=%5B0%20%5C%3Ah%2C%20%5Cfrac%7B1%7D%7B3%7D%20%5C%3Ah%5D)
is
We know that acceleration is the derivative of speed. So, by the Mean Value Theorem, there is a time c in 
at which .
c is a time time between 2:00 and 2:20 at which the acceleration is .
Gradient = 5
9 = 5 + c
C = 4
Answer:
Y=5x+4
Answer:
3.5132719e+24
Step-by-step explanation:
Is this a graphing question or…
