A dresser contains six pairs of shorts one each in the colors, red, black, blue, green, khaki, and gray. The dresser also contai
ns four shirts one each in the colors black, navy, red, gray. Melanie has to get dressed in the dark, so she grabs A pair of shorts and a T-shirt at random. What is the probability that she selects a green pair shorts and a gray T-shirt? (First of all, Melanie, you should really get a lamp. And second why is it you own more shorts than shirts?)
A = selects green pair of shorts B = selects gray t-shirt
P(A) = probability of selecting green shorts P(A) = (number of green shorts)/(number of shorts total) P(A) = 1/6 P(B) = probability of selecting gray t-shirt P(B) = (number of gray t-shirts)/(number of t-shirts total) P(B) = 1/4
P(A and B) = probability of selecting green shorts AND gray t-shirt P(A and B) = P(A)*P(B) ... since A and B are independent events P(A and B) = (1/6)*(1/4) P(A and B) = (1*1)/(6*4) P(A and B) = 1/24
Note: The fraction 1/24 is approximately equal to 0.041667
637 is the answer because our value is 980 we all know the unknown value with x for the step above 980 and 100% and 65% is the result in a pair of a simple equations
