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Crazy boy [7]
3 years ago
13

Carmen, Reuben, and Jim sent a total of 156 text messages over their cell phones during the weekend. Jim sent 6 fewer messages t

han Carmen. Reuben sent 4
times as many messages as Jim. How many messages did they each send?
Mathematics
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

1) determine what we know. We know that...

a) 156 total messages were sent

b) Jim sent 6 less that carmen

c) reuben sent 4 times as many as jim

2) create an equation with the information we know

(J= amount of messages jim sent, R= amount of messages reuben sent and C= amount of messages carmen sent)

(jim)         (reuben)     (carmen)    (total)

C - 6     +    J(4)    +    C            = 156

Now, isolate "C" on one side of the "="

3) add 6 to both sides of the equation:

C - 6 + J(4) + C =156

   -6                  -6

C + J(4) + C = 150

4) Combine like terms. In this case, combine the two Cs into Cx2:

C(2) +J(4) = 150

5) subtract "J(4)" from both sides of the "="

C(2) + J(4) = 150

        -J(4)     -J(4)

C(2) = 150 - J(4)

6) to isolate just 1 C, divide everything by 2

{C(2) = 150 - J(4)} ÷ 2

C = 75 - J(2)

7) Go back to our original equation (in bold) and replace "C" with "75 - J(2)"

(75-J(2)-6) + J(4) + (75-J(2)) = 156

Now solve for J.

Thats as far as I got.

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At the market, 777 apples cost \$4.55$4.55dollar sign, 4, point, 55. how much do 999 apples cost? \$
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6 0
3 years ago
The base of an aquarium with given volume V is made of slate and the sides are made of glass. If slate costs five times as much
Y_Kistochka [10]

Answer:

x = ∛ 2*V/5  

y = ∛ 2*V/5

h  = V/ ∛ 4*V²/25

Step-by-step explanation:

Dimensions of the aquarium base is  x*y

We call c₁ cost per unit area of the sides, then cost per unit area of slate is equal 5c₁.

let call h the height of the aquarium then volume of the aquarium is:

V = x*y*h      where   h =  V / x*y

As the base is a rectangular one there are 2 sides x*h .  and 2 sides  y*h

According to this:

Ct (cost of aquarium )  = cost of the base  + cost of the sides

cₐ  ( cost of the base) = 5*c₁*x*y

c₆ (cost of the sides ) = c₁*2*x*h   +   c₁*2*y*h

C(t)  =  5*c₁*x*y +2* c₁*x* V/x*y  +  2* c₁*y* V/x*y    or

C(t)  =  5*c₁*x*y  + 2*c₁*V/y   *2*c₁* V/x

Taking partial derivatives en x and y we have:

C´(x)  =  5*c₁*y - 2*c₁*V/x²

C´(y)  =  5*c₁*x - 2*c₁*V/y²

C´(x)  = C´(y)        ⇒  5*c₁*y - 2*c₁*V/x²  =   5*c₁*x - 2*c₁*V/y²

or    5*y - 2*V/x²  =   5*x - 2*V/y²

(5*y*x² - 2*V)/x²  = ( 5*y²x - 2*V) /y²

(5*y*x² - 2*V)*y²  = ( 5*y²x - 2*V)*x²

5*y³*x² - 2*V*y²  =  5*y²x³  - 2*V*x²

5*y³*x² - 5*y²x³  =  2*V * ( y² - x²)

by symmetry  x =  y

Then using x = y  and plugging that value on the derivatives

C´(x) =  5*c₁*y - 2*c₁*V/x²

C´(x) =  5*c₁*x - 2*c₁*V/x²

C´(x) = 0          ⇒     5*c₁*x - 2*c₁*V/x²  = 0

5*x  - 2*V/x² = 0      ⇒  5*x³ - 2*V = 0   ⇒   5*x³  = 2*V  ⇒ x³ = 2*V/5

x = ∛ 2*V/5       and   y = ∛ 2*V/5    and   h  =  V/ x*y    h  = V/ ∛ 4*V²/25

7 0
3 years ago
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