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Crazy boy [7]
2 years ago
13

Carmen, Reuben, and Jim sent a total of 156 text messages over their cell phones during the weekend. Jim sent 6 fewer messages t

han Carmen. Reuben sent 4
times as many messages as Jim. How many messages did they each send?
Mathematics
1 answer:
jolli1 [7]2 years ago
7 0

Answer:

Step-by-step explanation:

1) determine what we know. We know that...

a) 156 total messages were sent

b) Jim sent 6 less that carmen

c) reuben sent 4 times as many as jim

2) create an equation with the information we know

(J= amount of messages jim sent, R= amount of messages reuben sent and C= amount of messages carmen sent)

(jim)         (reuben)     (carmen)    (total)

C - 6     +    J(4)    +    C            = 156

Now, isolate "C" on one side of the "="

3) add 6 to both sides of the equation:

C - 6 + J(4) + C =156

   -6                  -6

C + J(4) + C = 150

4) Combine like terms. In this case, combine the two Cs into Cx2:

C(2) +J(4) = 150

5) subtract "J(4)" from both sides of the "="

C(2) + J(4) = 150

        -J(4)     -J(4)

C(2) = 150 - J(4)

6) to isolate just 1 C, divide everything by 2

{C(2) = 150 - J(4)} ÷ 2

C = 75 - J(2)

7) Go back to our original equation (in bold) and replace "C" with "75 - J(2)"

(75-J(2)-6) + J(4) + (75-J(2)) = 156

Now solve for J.

Thats as far as I got.

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Step-by-step explanation:

This is asking for speed.

Speed=Distance/Time

Speed=720/9

Speed=80 km/hr

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Julien threw x number of pitches at baseball practice. Jacob threw 1/5 fewer than that
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Step-by-step explanation:

if you say julien threw x and jacob threw 1/5 of that than jacob threw 1/5 of x

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You can convert the fraction to a decimal form.
7/9 is .778 
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44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
I need help Pls help with both
Gwar [14]

Answer:

the first one is 84

Step-by-step explanation:

subtract 145-61 then you get 84for the missing angle.

7 0
2 years ago
Read 2 more answers
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