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Pie
3 years ago
15

If h = 21 units and r = 7 units, what is the volume of the cone shown above? Use 3.14 for .

Mathematics
1 answer:
icang [17]3 years ago
3 0
Both same unit so multiply your numbers to get a great digits
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How many solutions does
eimsori [14]

Answer:

The above equation has two solution

x = 0 and x = 1

Step-by-step explanation:

[ refer to the attachment ]

7 0
3 years ago
Which of the following ordered pairs is a solution of the line y-2x=6
Novay_Z [31]

<u><em>Answer:</em></u>

<u><em>x = -3 + Y/2</em></u>

<u><em>y= 6 +  2x</em></u>

<u><em>Hope this helps!:3</em></u>

7 0
3 years ago
Assume that you want to replace your sailboat with a larger one in 3 years. To save for a
Darina [25.2K]

Answer: $11,600

Step-by-step explanation:

$2000 * 10% = $200

y = 200x + $2,000

12 * 4 = 48

48 = x

y = 200(48) + $2,000

y = $9,600 + $2,000

y = $11,600

8 0
3 years ago
How do you convert 24411.41178 to money form?​
cricket20 [7]
In money form there can’t be more than two decimal places so it’s $24,411.41
3 0
3 years ago
Which of the following is NOT a linear factor of the polynomial function?
Natalija [7]

Answer:

Among the four choices, (x + 5) is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let a denote some constant. A linear factor of the form (x - a) is a factor of a polynomial f(x) if and only if f(a) = 0 (that is: replacing all x in the polynomial f(x) \! with the constant a\! would give this polynomial a value of 0.)

For example, in the second linear factor (x - 2), the value of the constant is a = 2. Verify that the value of f(2) is indeed 0. (In other words, replacing all x in the polynomial f(x) \! with the constant 2 should give this polynomial a value of 0\!.)

\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}.

Hence, (x - 2) is indeed a linear factor of polynomial f(x).

Similarly, it could be verified that (x - 5) and (x + 2) are also linear factors of this polynomial function.

Rewrite the first linear factor (x + 5) in the form (x - a) for some constant a: (x + 5) = (x - (-5)), where a = -5.

Calculate the value of f(5).

\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}.

f(5) \ne 0 implies that (x - (-5)) (which is equivalent to (x + 5)) isn't a linear factor of this polynomial function.

3 0
3 years ago
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