Answer:

Step-by-step explanation:
For each right-angled triangle:

Because 
we have an equation

multiplying both sides by x, we get 
dividing both sides by 0.4 and 
using calculator, we divide 12 by 0.4
and finally x=30
Answer:
2 because it holds the same value as -2 and its the additive inverse
Answer:
80
Step-by-step explanation:
Answer:
A, B and C
Step-by-step explanation:
Given any three side lengths of a right triangle, the longest side is the hypotenuse.
The side lengths of a right triangle must satisfy the <u>Pythagorean Theorem. </u>
Pythagorean Theorem: 
<u>Option A:</u> 

True
<u>Option B:</u> 2.5, 6, 6.5

<u>Option C:</u> 

Since all are true, the side lengths in Options A, B and C forms a right triangle,
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>