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deff fn [24]
2 years ago
10

Can you help me slove this 4 - 2x = 10

Mathematics
1 answer:
melomori [17]2 years ago
4 0

Answer:

x = -3

Step-by-step explanation:

First we take the equation below.

4 - 2x = 10

Subtract 4 from each side because of the subtraction property of equality.

-2x=6

Divide both sides by -2 to isolate the x. (Division property of equality

x=-3

We now know that x = -3.

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d ) f(x)= -5x-19 is most likely

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5000 is a four digit whole number, which means it has a place value of 5000
5 thousands 0hundreds 0tens 0ones

5000 is 100 times greater than 50
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A person x inches tall has a pulse rate of y beats per​ minute, as given approximately by yequals600 x Superscript negative 1 di
tankabanditka [31]

Answer:

a) 5.13beats/min

b) 2.82 beats/min

Step-by-step explanation:

Given the pulse rate of a person modelled by the equation y = 600x^-1/3 for 30≤x≤75

If the height is 39inches, the instantaneous rate of change of pulse rate for the heights will be expressed as;

y = 600(39)^-1/3

y = {600(1/39)}/3

y = 600/39×3

y = 600/117

y ≈ 5.13beats/min

The instantaneous rate for a 39 inches tall person is 5.13 beats per min

b) For a 71inches tall person, the beat rate will be expressed as;

y = 600(71)^-1/3

y = {600(1/71)}/3

y = 600/71×3

y = 600/213

y ≈ 2.82 beats per minute

The instantaneous rate for a 71 inches tall person is 2.82 beats per min

7 0
3 years ago
A pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. The height, h, of th
Gennadij [26K]
<h2>Explanation:</h2>

In this problem we have a pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. So the height, h, of the pumpkin at time t seconds after the launch can be modeled by the equation:

h(t) = -16t^2 + 84t + 20

So this is the equation of a parabola. The maximum of this parabola occurs at its vertex. So let's find this vertex:

\text{The x-value of the vertex is}: \\ \\ t=-\frac{b}{2a} \\ \\ \\ Where: \\ \\ a=-16 \\ \\ b=84 \\ \\ c=20 \\ \\ \\ t=-\frac{84}{2(-16)} \\ \\ t=-\frac{84}{-32} \\ \\ t=\frac{21}{8}=2.625 \\ \\ h(2.625)=-16(2.625)^2+84(2.625)+20 \\ \\ h(2.625)=-110.25+220.5+20 \\ \\ h(2.625)=130.25m

Finally, the maximum occurs at time 2.625 seconds when the height is 130.25m

8 0
3 years ago
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