I think I may be wrong check
5(x^2n-1)×(2x^3n-1) ^2
=20n3 x8 -20n2 x5 +20n x3 +20n x3 +5n x2-5
Answer:
This is 0.14 to the nearest hundredth
Step-by-step explanation:
Firstly we list the parameters;
Drive to school = 40
Take the bus = 50
Walk = 10
Sophomore = 30
Junior = 35
Senior = 35
Total number of students in sample is 100
Let W be the event that a student walked to school
So P(w) = 10/100 = 0.1
Let S be the event that a student is a senior
P(S) = 35/100 = 0.35
The probability we want to calculate can be said to be;
Probability that a student walked to school given that he is a senior
This can be represented and calculated as follows;
P( w| s) = P( w n s) / P(s)
w n s is the probability that a student walked to school and he is a senior
We need to know the number of seniors who walked to school
From the table, this is 5/100 = 0.05
So the Conditional probability is as follows;
P(W | S ) = 0.05/0.35 = 0.1429
To the nearest hundredth, that is 0.14
Answer:
theres no picture
Step-by-step explanation:
Answer:
Step-by-step explanation:
We have been given that there are total 9 people who entered the drawing competition. There are 3 prizes to be distributed to the winners. The total number of ways that 3 prizes can be awarded to the 9 people can be determined as 9*8*7 = 504.
The total number of ways in which I win the first prize and my mom wins the second prize would be 1*1*7 = 7.
Therefore, the probability that I win the first prize and my mom wins the second prize would be: 
Answer:
Each pair costs $8.86
Step-by-step explanation:
Divide 35.45 by 4
You get 8.8625
Round that to the nearest hundredth.
You get $8.86
Hope this helped!
