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Scrat [10]
4 years ago
8

What is the decimal 89.023 in word and expanded form

Mathematics
2 answers:
Rzqust [24]4 years ago
4 0

Answer: Eighty Nine and Twenty Three Thousandths

Step-by-step explanation:

givi [52]4 years ago
3 0

Answer:

eighty-nine and twenty-three thousandths <------ word form

80 + 9 + 0.02 + 0.003 <------ expanded form

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There was some chicks in 4 coops. How many chicks were in each coop?
kondaur [170]

Answer:

There is not enough information to solve.

Step-by-step explanation:

We need to know how many chicks there were in total. Then, divide the total number of chicks by the 4 coops and that will be your answer.

7 0
3 years ago
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What numbers go into 120
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The numbers that go into 120 are 10,12 and 6,20 and 3,40,. That's all I can think of at the moment.
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What is the value of x enter your answer in the box x=
lions [1.4K]

Answer:

<u>x = (3√34 + 1)/5 units</u>

Step-by-step explanation:

Let's solve for x, using the Pythagorean theorem, this way:

BC is the Hypotenuse of the triangle ABC

BC² = 15² + 9²

BC² = 225 + 81

BC² = 306

BC = √9 * 34

BC = 3 √34

Now, we can substitute and solve for x, this way:

BC = 3x + 2x - 1

3 √34 = 3x + 2x - 1

3√ 34 + 1 = 5x

<u>x = (3√34 + 1)/5 units</u>

3 0
3 years ago
Examine the given sequence. Which statement is not correct
Eddi Din [679]

Answer:

Examine the given sequence. Which statement is not correct?

A) If c = 14, the relationship is linear and f(x) = 2x + 8 for x = {1, 2, 3, ...}.  

B) If c = 14, the relationship is linear and an = 10 + 2(n − 1) for n = {1, 2, 3, ...}.  

C) If c = 14.4, the relationship is exponential and f(x) = 10(1.2)(x − 1) for x = {1, 2, 3, ...}.  

D) If c = 14.4, the relationship is exponential. a1 = 10 and an + 1 = an + 1.2 for n = {1, 2, 3, ...}.

Step-by-step explanation:

6 0
3 years ago
1) A traditional die is a cube with each of its six sides representing the numbers from 1 to 6. Mr. Dicey customized a die by re
liraira [26]

Answer:

1) \frac{2}{5}

2) 49.225

3) \frac{7}{2}

Step-by-step explanation:

1) To find the expected value of the dice we can use the following equation:

E(x)=x_{1}*P(x_{1})+x_{2}*P(x_{2})+...+x_{n}*P(x_{n})

So in our problem the values x will be: 1/1, 1/2, 1/3, 1/4, 1/5 and 1/6 and the probavility for all values is 1/6 so the expected values will be:E(x)=(\frac{1}{1} *\frac{1}{6}) +(\frac{1}{2} *\frac{1}{6}) +(\frac{1}{3} *\frac{1}{6})+(\frac{1}{4} *\frac{1}{6})+(\frac{1}{5} *\frac{1}{6})+(\frac{1}{6} *\frac{1}{6})

E(x)=0.167+0.083+0.056+0.042+0.033+0.028=0.409\approx \frac{2}{5}

2) To find the variance of the expected values we can use the equation:

Var(x)=\frac{\sum_{i=1}^{n}(x_{i}-\overline{x})^{2} }{n}

So for our problem will be:

Var(x)=\frac{(3-10.5)^2+(4-10.5)^2+(17-10.5)^2+(18-10.5)^2}{4}

Var(x)=\frac{56.25+42.25+42.25+56.25}{4}Var(x)=\frac{196.9}{4}=49.225

3) To find the expected value of the dice we can use the following equation:

E(x)=x_{1}*P(x_{1})+x_{2}*P(x_{2})+...+x_{n}*P(x_{n})

So in our problem the values x will be: 1, 2, 3, 4, 5 and 6 and the probavility for all values is 1/6 so the expected values will be:E(x)=(1*\frac{1}{6}) +(2 *\frac{1}{6}) +(3 *\frac{1}{6})+(4 *\frac{1}{6})+(5 *\frac{1}{6})+(6 *\frac{1}{6})

E(x)=0.17+0.33+0.5+0.67+0.83+1=3.5\approx \frac{7}{2}

7 0
3 years ago
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