Question

If a particle’s position is given by the equation s(t) = 2t^3 − 15t^2 + 2, what is the acceleration at time t = 3?

Answer 1

Answer:

6

Explanation:

take the 2nd derivative.

first derivative: 6t^2 -30t

2nd derivative: 12t-30

1st derivative: velocity

2nd derivative: acceleration

12(3)-30 = 6