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3 years ago

10

The path of the sun on the celestial sphere is called.

1 answer:

Ede4ka [16]3 years ago

7 0

Answer:

Ecliptic

Explanation:

The path the sun, moon, and planets take across the sky as seen from Earth. It defines the plane of the Earth's orbit around the sun. The name "Ecliptic" comes from the fact that eclipses take place along this line.

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Initial velocity=3m/s, final velocity=5m/s, displacement=2m. Find the acceleration.

shusha [124]

Answer:

Explanation:

To analyze the behavior of black bears during the night. To describe how black bears adapt to life near human. To evaluate the decline in the number of black bear.

4 0

3 years ago

Read 2 more answers

A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 13 A, while that

Feliz [49]

Answer:

(a) 1560 W

(b) 576 W

(c) 1.01

Explanation:

Voltage, V = 120 V

Current in dryer, I = 13 A

current in vacuum cleaner, i' = 4.8 A

(a) Power consumed by dryer,

P = V I = 120 x 13 = 1560 W

(b) Power consumed by vacuum cleaner

P' = V I' = 120 x 4.8 = 576 W

(c) Energy consumed by dryer

E = P x t = 1560 x 15 x 60 = 1404000 J

Energy consumed by the vacuum cleaner

E' = P' x t' = 576 x 40 x 60 = 1382400 J

the ratio of energies is

E : E' = 1404000 : 1382400 = 1.01

3 0

3 years ago

kap26 [50]

S = 10 + (-4) = 6

Displacement is vector quantity

5 0

3 years ago

A 4-kg block and a 2-kg block can move on the horizontal frictionless surface. The blocks are accelerated by a+12-N force that p

lozanna [386]

Answer:

$F_n = -4 N$

Explanation:

Net external force that exerted on the block is given as

$F_{net} = (m_1 + m_2) a$

here we know that

$F = 12 N$

$m_1 = 4 kg$

$m_2 = 2 kg$

now we have

$12 = (4 + 2) a$

so we have

$a = 2 m/s^2$

now the force exerted by bigger block on smaller block is given as

$F_n = ma$

$F_n = (2 \times 2)$

$F_n = 4 N$

now we know that two blocks will exert equal and opposite force on each other

so here the force exerted by 2 kg block on 4 kg block will be

$F_n = -4 N$

5 0

3 years ago

A bathtub has 62.7 kg of water at 31.0

Bogdan [553]

m = mass of water in bathtub = 62.7 kg

$T_{ti}$ = initial temperature of water in tub = 31 c

M = mass of water added = ?

$T_{ai}$ = initial temperature of water added = 76 c

T = final equilibrium temperature of the system = 40.3 c

c = specific heat of water = 4186

Using conservation of heat

Heat gained by water in tub = Heat lost by water added

m c (T - $T_{ti}$ ) = M c ( $T_{ai}$ - T)

m (T - $T_{ti}$ ) = M ( $T_{ai}$ - T)

(62.7) (40.3 - 31) = M (76 - 40.3)

M = 16.3 kg

5 0

3 years ago