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Viktor [21]
3 years ago
8

If it takes you 10 seconds to increase from 0 km/h to 50 km/h, what is your acceleration?

Physics
2 answers:
ZanzabumX [31]3 years ago
4 0
Acceleration is change in velocity over change in time. Your Δv is +13.9, since you increased speed by 50 km/h which is 13.9 m/s, and your Δt is 10s. 13.9/10 = 1.39 m/s^2, the standard units for acceleration. Make sense?
Licemer1 [7]3 years ago
3 0
In order to figure this out you use the equation acceleration = final velocity - initial velocity / time. or a = vf-vi/t. So a = 50 km/h - 0 km/h / 10 seconds. Since 50 - 0 is 50, 50 divided by 10 is 5. So you acceleration is 5 km/h plus the direction you are traveling. So your answer should look like a=5km/h + direction
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Answer:

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Explanation:

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WILL MARK AS BRAINLIEST!!!!!!
yaroslaw [1]

M1V1 + M2V2 = M1V1' + M2V2'

where:

M1 is the mass of the large marble = 0.05 kg

V1 is the initial velocity of the large marble = 0.6 m/sec

M2 is the mass of the small marble = 0.03 kg

V2 is the initial velocity of the small marble = 0 m/sec (marble is at rest)

V1' is the final velocity of the large marble = -0.2 m/sec

V2' is the final velocity of the small marble that we want to calculate

Substitute with the givens in the above equation to get V2' as follows:

M1V1 + M2V2 = M1V1' + M2V2'

(0.05)(0.6) + (0.03)(0) = (0.05)(-0.2) + 0.03V2'

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4 0
3 years ago
If the speed of light is 1.5times that of the speed of light in a given material what is the index of refraction for that materi
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The answer is 1.5....
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8 0
3 years ago
A bike is traveling to the left with the speed of 27 m/s when the rider slams on the brakes. The bike skids for 41.5 m with the
Darina [25.2K]

The acceleration of the bike is equal to 8.78\frac{m}{s^{2}} opposing the movement (to the right).

Why?

Since after the rider slams the brakes, the bike came to a stop, we know that the acceleration is opposite to the velocity/movement.

We can use the following equation to calculate the acceleration:

v_{f}^{2}=v_{o}^{2}+2*a*d

So, substituting, we have: (let's consider negative to the left and positive to the right)

0=(-27\frac{m}{s} )^{2}+2*a*41.5m\\\\0=729\frac{m^{2} }{s^{2} }+83*a\\\\a=\frac{-729\frac{m^{2}}{s^{2}}}{83m}=-8.78\frac{m}{s^{2}}

The negative sign means that the acceleration's direction is opposite to the movement.

Hence, we have that the acceleration is equal to 8.78\frac{m}{s^{2}} opposing the movement (to the right).

Have a nice day!

5 0
4 years ago
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