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avanturin [10]
3 years ago
11

PLZZZZZ! HELP! I'll give brainliest to the first correct answer, five stars, and a heart!

Physics
1 answer:
Musya8 [376]3 years ago
7 0

Answer:

frequency: 2nd choice

period: 4th choice

amplitude: 1st choice

wavelength: 3rd choice

speed: 5th choice

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Please help me with my quiz
Oduvanchick [21]

Answer:

matter: A

data: E

variable: C

Controlled: D

Physical: B

Explanation:

8 0
2 years ago
What is the period of a wave traveling 5 m/s if its wavelength is 20 m/s
Ilia_Sergeevich [38]

Speed of wave is given as

v = 5 m/s

Wavelength of the wave is given as

\lambda = 20 m

now from the formula of wave time period we can say

speed = \frac{wavelength}{time period}

5 = \frac{20}{T}

T = \frac{20}{5}

T = 4 s

so it will have time period of T = 4 s

7 0
3 years ago
Hi i need help pls help me
r-ruslan [8.4K]
The correct answer would be the last one
4 0
2 years ago
Read 2 more answers
Two<br>vectors Å and °B are such that A = 2<br>and A-B-C find the angle between them​
sweet-ann [11.9K]

Answer:

hjg567 A 567

Explanation:

7 0
3 years ago
A small metal bead, labeled A, has a charge of 28 nC .It is touched to metal bead B, initially neutral, so that the two beads sh
Dmitry_Shevchenko [17]

Answer:

Explanation:

Let the charge on bead A be q nC  and the charge on bead B be 28nC - qnC

Force F between them

4.8\times10^{-4} = \frac{9\times10^9\times q\times(28-q)\times10^{-18}}{(5\times10^{-2})^2}

=120 x 10⁻⁸ = 9 x q(28 - q ) x 10⁻⁹

133.33 = 28q - q²

q²- 28q +133.33 = 0

It is a quadratic equation , which has two solution

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3 years ago
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