P = 4x + 2y
additional info.
<span>x+2y <u><</u> 10
y <u><</u> 2
x <u>></u> 0
y <u>></u> 0
y can only be 0, 1, and 2.
x + 2(0) <u><</u> 10 = x <u><</u> 10
x + 2(1) <u><</u> 10 = x + 3 <u><</u> 10 = x <u><</u> 10 - 3 = x <u><</u> 7
x + 2(2) <u><</u> 10 = x + 4 <u><</u> 10 = x < 10 - 4 = x <u><</u> 6
x = 10 ; y = 0 : P = 4(10) + 2(0) = 40 + 0 = 40
x = 7 ; y = 1 : P = 4(7) + 2(1) = 28 + 2 = 30
x = 6 ; y = 2 : P = 4(6) + 2(2) = 24 + 4 = 28
The maximum value of P is 40. Where x is 10 and y is 0.</span>
Answer:
(c)
"The given statement is true, by definition of length of a vector
,
"
Step-by-step explanation:
(a) 
That is completely correct Remember that if
then

Therefore the correct answer would be (c).
"The given statement is true, by definition of length of a vector
,
"
Answer:
6√2
Step-by-step explanation:
Given,
θ = 45
Opposite side = 6
To find : - Hypotenuse
Formula : -
sin θ = Opposite side / Hypotenuse
[ The value of sin 45 = 1 / √2 ]
sin 45 = 6 / Hypotenuse
1 / √2 = 6 / Hypotenuse
Cross multiply,
Hypotenuse = 6√2
Answer:
4:24 p.m.
Step-by-step explanation:
Figure out how often the buses leave at the same time. This is the same as the least common multiple (LCM) of how often they leave the stadium.
The LCM is found by multiplying the maximum number of each prime factor found in any of the numbers.
The prime factors of a number are found by dividing it by whole numbers until the factors are all prime. Prime numbers only have the factors 1 and itself.
6 = 2 X 3
8 = 2 X 2 X 2
The greatest times 2 repeats is three times.
The greatest times 3 repeats is one time.
2 X 2 X 2 X 3 = 24
The LCM is 24, and the buses have the same leaving times every 24 minutes.
Find 24 minutes after 4:00 p.m. Change the minutes only, which are the numbers right of the colon : .
The buses will next leave together at 4:24 p.m.