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3 years ago

Find the highest common factor and lowest common multiple of 60 and 150 using prime factors

1 answer:

7 0

Here, we know, 60 = 2 × 30
& 150 = 5 × 30

So, Highest Common Factor (HCF) would be 30

Now, Lowest common point = 60 × 5 = 300 or 150 × 2 = 300

In short, LCM would be 300

Hope this helps!

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Please help :( Orlando is making a design for a logo. He begins with a square measuring 20 inches on a side. The second square h

Naddik [55]

Answer:D

Step-by-step explanation:

1st --- 20

2nd -- 16

3rd -- 12.8

4th -- 10.24

5th -- 8.192

6th -- 6.5536

3 0

3 years ago

Solve and check the following equation algebraically. 1/2(x + 32) = -10

ANTONII [103]

Solve :
1/2(x + 32) = -10....multiply both sides by 2
x + 32 = -10 * 2
x + 32 = -20
x = -20 - 32
x = - 52 <===

check :
1/2(x + 32) = -10.....when x = -52
1/2(-52 + 32) = -10
1/2(-20) = -10
-20/2 = -10
-10 = -10 (correct)

8 0

3 years ago

Read 2 more answers

How to find the derivative of this?

dimulka [17.4K]

I cant see all the question but this is how you find the derivative of your function using the product rule.

Here you use the extension of the product rule to 3 factors which we'll write as:-

f(x), g(x) and h(x):-

Derivative = f'(x) g(x) h(x) + f(x) g'(x) h(x) + f(x) g(x) h'(x)

(3x - 1)(x + 4)(2x - 1)

derivative = 3(x + 4)(2x - 1) + (3x + 1)(1)(2x - 1) + (3x - 1)(x + 4)(2)

= 3(x + 4)(2x - 1) + (3x + 1)(2x - 1) + 2(3x - 1)(x + 4)

4 0

3 years ago

If cos 0 =8/17, what is sin 0?

ipn [44]

Answer:

sin=15/17

Step-by-step explanation:

Use the definition of sine to find the value of

sin (0)

sin (0) = opp/hyp

THEN

Substitute in the known values.

sin (0) = 15/17

3 0

2 years ago

Solve the following systems by substitution

Paladinen [302]

Answer:

The answer to your question is below

Step-by-step explanation:

Question 1

x = 5 Equation l

2x + y = 10 Equation ll

- Substitute Equation l in equation ll

2(5) + y = 10

y = 10 - 10

y = 0

- Solution (5, 0)

Question 2

x + 16y = 20 Equation l

x = 4y Equation ll

Substitute equation ll in equation l

4y + 16y = 20

20y = 20

y = 20/20

y = 1

-Find x

x = 4(1)

x = 4

-Solution

(4, 1)

Question 3

2x + 8y = 20 Equation l

x = 2 Equation ll

-Substitute equation ll in equation l

2(2) + 8y = 20

4 + 8y = 20

8y = 20 - 4

8y = 16

y = 16/8

y = 2

- Solution

(2, 2)

8 0

4 years ago