The rotational symmetry has more than one order of rotational symmetry the objects can fit itself within 360 degrees.
Answer:
Step-by-step explanation:
3x+18>2x
3x-2x>-18
x>-18
23/4 i swear that’s the answer hope it helps
Answer:

Step-by-step explanation:
Let's rewrite the left side keeping in mind the next propierties:


Therefore:

Now, cancel logarithms by taking exp of both sides:

Multiply both sides by
and using distributive propierty:

Substract
from both sides and factoring:

Multiply both sides by -1:

Split into two equations:

Solving for 
Add 4 to both sides:

Solving for 
Collect in terms of x and add
to both sides:

Divide both sides by e-2:

The solutions are:

If we evaluate x=4 in the original equation:

This is an absurd because log (x) is undefined for 
If we evaluate
in the original equation:

Which is correct, therefore the solution is:

Answer:
The result will be smaller than 2.6s, 16% of the time.
Step-by-step explanation:
This is a normal distribution problem
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - xbar)/σ
x = the random value = 2.6 s
xbar = mean = the average = 3.4 s
σ = standard deviation = 0.8 s
z = (2.6 - 3.4)/0.8 = - 1
P(x < 2.6) = P(z < - 1) = 1 - P(z ≥ - 1) = 1 - P(z ≤ 1) = 1 - 0.841 = 0.159 = 16%