Question

Graphing in Point-Slope Form y−y1=m(x−x1) ​ Graph the equation y+7=−45(x−4) ?

Answer 1

Answer:

The graph is in the attachment.

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - a point on a line

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

We have the equation in a point-slope form:

$y+7=-\dfrac{4}{5}(x-4)$

$y-(-7)=-\dfrac{4}{5}(x-4)$

Therefore we have one point: (4, -7).

Convert to the slope-intercept form:

$y+7=-\dfrac{4}{5}(x-4)$              use the distributive property

$y+7=-\dfrac{4}{5}x+\left(-\dfrac{4}{5}\right)(-4)$

$y+7=-\dfrac{4}{5}x+\dfrac{16}{5}$

$y+7=-\dfrac{4}{5}x+3\dfrac{1}{5}$          subtract 7 from both sides

$y=-\dfrac{4}{5}x-3\dfrac{4}{5}$

Put x = -1 to the equation:

$y=-\dfrac{4}{5}(-1)-3\dfrac{4}{5}=\dfrac{4}{5}-3\dfrac{4}{5}=-3$

Therefore we have the second point (-1, -3).