Answer:
If one buoy is placed 120 feet away from the left shore, then the distance of the second buoy from the left shore = 480
Step-by-step explanation:
Given that:
The absolute value function:
To calculate the position of the buoy where the river bottom is 20 feet below the surface, we equate the absolute value function to the negative value of 20 feet and then solve it for h.
d(h) = -20
Let us add the sum of 50 on both sides, then:
By multiplying 6 on both sides, we have:
|h - 300| = 30 (6)
|h - 300| = 180
We can attempt the above expression by rewriting it as two equations:
h - 300 = 180 or h - 300 = - 180
Let us add 300 to both sides from the two expressions above:
h - 300 + 300 = 180 + 300 or h - 300 + 300 = -180 + 300
h = 480 or h = 120
Thus, if one buoy is placed 120 feet away from the left shore, then the distance of the second buoy from the left shore = 480
<A +<B + < C =180° ==>(5x+6) + (2x+1) + (6x+4) = 180°
13x = 180°-11° ==> 13x 169° and x =169/13 =13°
305 11/45
Step by step explanation
Hello, and thanks for posting your question!
A function would be a set of ordered pairs that have no repeating "x" values, look at the example below. (V)
{(1, 0), (2, 0), (3, 0)} = Function
{(1, 0), (1, 0), (2, 0)} = Not a function.
According to this information, your answer is C. Both Set A and Set B.
Hope this helps! ☺♥
Answer:
A| 12, 3
Step-by-step explanation:
The polynomial can be factored by looking for factors of 36 that sum to -15. The sum being negative while the product is positive means both factors will be negative. The answer choices suggest ...
y = (x -12)(x -3)
A quick check shows this product is ...
y = x^2 -12x -3x +36 = x^2 -15x +36 . . . . as required
The factors are zero when x is either 12 or 3.
The zeros of the equation are 12 and 3.
____
Once you realize the constants in the binomial factors both have a negative sign, you can immediately choose the correct answer (A).
Or, you can use Descartes' rule of signs, which tells you that the two sign changes in the coefficients (+-+) mean there are 2 positive real roots.
