<u>ANSWER:</u>
The midpoint of AB is M(-5,1). The coordinates of B are (-6, 7)
<u>SOLUTION:
</u>
Given, the midpoint of AB is M(-5,1).
The coordinates of A are (-4,-5),
We need to find the coordinates of B.
We know that, mid-point formula for two points A
and B 
is given by
Here, in our problem, 
Now, on substituting values in midpoint formula, we get
On comparing, with the formula,
Hence, the coordinates of b are (-6, 7).
Plugging it in, we get (3)(2)+2y=-12 and 6+2y=-12. Subtracting 6 from both sides, we get -18=2y and dividing by 2 we get y=-9 to get (2, -9) since x is first in the pair
Now, there are 360° in a circle, how many times does 360° go into 1860°?
well, let's check that,
now, this is a negative angle, so it's going
clockwise, like a clock moves, so it goes around the circle clockwise 5 times fully, and then it goes 1/6 extra.
well, we know 360° is in a circle, how many degrees in 1/6 of 360°? well, is just 360/6 or their product, and that's just 60°.
so -1860, is an angle that goes clockwise, negative, 5 times fully, then goes an extra 60° passed.
5 times fully will land you back at the 0 location, if you move further down 60° clockwise, that'll land you on the IV quadrant, with an angle of -60°.
therefore, the csc(-1860°) is the same as the angle of csc(-60°), which is the same as the csc(360° - 60°) or csc(300°).
7^5. Found by trial and error.
