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3 years ago

5

A nonstop flight from Houston to Jacksonville takes x hours (travelling at 410 m/h). The return flight takes 30 minutes longer.

What is the distance from Houston to Jacksonville.

2 answers:

andriy [413]3 years ago

7 0

I do in fact believe that the answer to your question is the number 456

Nadusha1986 [10]3 years ago

4 0

Answer:

456 Miles

Step-by-step explanation:

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On their first day of vacation, a family spent $127.92 for meals. The family spent $160.01 for meals the second day. By what amo

ehidna [41]

Answer:

D=32.09

Step-by-step explanation:

160.01-127.92=32.09

5 0

2 years ago

Read 2 more answers

Simplify 4/7 + 5/6 whoever possible

Pani-rosa [81]

Hey there!

4/7 + 5/6

≈ 24/42 + 35/42

≈ 24 + 36/ 42 - 0

≈ 59/42

≈ 1 17/42

Therefore, your answer is:

59/42 or 1 17/42

EITHER OF THOSE SHOULD WORK BECAUSE THEY ARE EQUIVALENT.

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

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2 years ago

For the basic function f(x)=x, what conclusions can you make about f(x) and f(x)-5? Select all that apply.

babunello [35]

Answer:The ansewers are c and d.

Step-by-step explanation:

The function f(x)=x is really y=x.

7 0

2 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers

3/7•d=9/14 in this<br> Problem you want to find what d equals

sertanlavr [38]

<u>→ Chapter : Fractions ←</u>
<u><em>≡ We know that:</em></u>
⇔ $(\frac{a}{b}) \div (\frac{c}{d})=(\frac{a}{b}) \times (\frac{d}{c})$

<u><em>≡ Solution:</em></u>
⇒ $(\frac{3}{7}) \times (d)=\frac{9}{14}$
⇒ $d=(\frac{9}{14}) \div (\frac{3}{7})$
⇒ $d=(\frac{9}{14}) \times (\frac{7}{3})$
∴ $\boxed{\frac{3}{2}}$

7 0

2 years ago