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2 years ago

Help please! Check my answer to see if it's right.

Mathematics

2 answers:

Anit [1.1K]2 years ago

6 0

Answer:

yes

Step-by-step explanation:

You have the correct intercepts

grigory [225]2 years ago

3 0

Answer:

Should be, yeah

Step-by-step explanation:

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Solve 2x²-x+3 in bull dover

liq [111]

Answer:

2x2 - x + 3

Step-by-step explanation:

8 0

3 years ago

6-2x=5x-9x+10 solve for x

andrew-mc [135]

X=2

So you solve for x by simplifying bath sides of the equation, then all you do is isolate the variables

7 0

3 years ago

Which characteristics best describe an acute isosceles triangle?

Paladinen [302]

Isocoleese means that 2 sides and hence 2 angles are same measure
acute means that all 3 angles are less than 90 degrees

We can rule out choice I since acut means less than 90

II is a possibility, but it doesn't best describe it

III. that is true, but it doesn't include the isocileese part

IV. that is true, but doesn't include the acute part

not sure, either III or IV

4 0

2 years ago

Read 2 more answers

32. A data set is normally distributed

KiRa [710]

Answer:

93.1%

Step-by-step explanation:

7 0

2 years ago

Evaluate the following

IRINA_888 [86]

(a) $[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

Answer:

$[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5*2.5 }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5}{1} ]^{2}$

*canceling 2.5 in numerator and denominator*

$= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925$

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) $[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3} ] ^{2}$

Answer:

$[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\$

*using $[x^{a}]^b = x^{ab}$ *

$= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}$

*Again, using $[x^{a}]^b = x^{ab}$ *

$= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} } \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1$

Property used: 'Power of a power'

We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

3 0

3 years ago