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Lemur [1.5K]
3 years ago
10

( 100 pts and brainliest )Which graph shows?

Mathematics
2 answers:
Rashid [163]3 years ago
8 0

Answer

Try looking up answer sheets for this question I don't know the answer but i would help you if i could.

Step-by-step explanation:

katrin [286]3 years ago
6 0

Answer:

Graph 3

Step-by-step explanation:

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Describe a way to find points that divide a segment into fourths.
velikii [3]
You must be given with the point of the whole line. Knowing that you would have 4 equal parts, there must be 5 divisions. The first thing to do is find the midpoint of the endpoints of the line to create a mid-partition. You now have 2 equal parts. Next, find the midpoint again for the 2 equal parts. You make 2 new parts again for each side. The total would be 4.

To find the midpoint, just find the average of the corresponding x- and y-coordinates of the 2 points. If point A(1,2) and point B is (3,4), the midpoint would be (2, 3).

7 0
4 years ago
I run a book club with n people, not including myself. Every day, for 365 days, I invite three members in the club to review a b
Bezzdna [24]
<h3>Answer:   15</h3>

========================================================

Explanation:

The order doesn't matter. A group like {A,B,C} is the same as {B,A,C}.

All that matters is the overall group rather than the positioning of the members.

We'll use the nCr combination formula since order doesn't matter.

The value of n is unknown, but we know that r = 3 members are to be selected.

Let's pick a value for n at random. Let's say n = 10.

Plug n = 10 and r = 3 into the nCr formula below.

n C r = \frac{n!}{r!(n-r)!}\\\\10 C 3 = \frac{10!}{3!*(10-3)!}\\\\10 C 3 = \frac{10!}{3!*7!}\\\\10 C 3 = \frac{10*9*8*7!}{3!*7!}\\\\ 10 C 3 = \frac{10*9*8}{3!}\\\\ 10 C 3 = \frac{10*9*8}{3*2*1}\\\\ 10 C 3 = \frac{720}{6}\\\\ 10 C 3 = 120\\\\

Unfortunately we don't reach 365 or larger.

Let's try n = 11

n C r = \frac{n!}{r!(n-r)!}\\\\11 C 3 = \frac{11!}{3!*(11-3)!}\\\\11 C 3 = \frac{11!}{3!*8!}\\\\11 C 3 = \frac{11*10*9*8!}{3!*8!}\\\\ 11 C 3 = \frac{11*10*9}{3!}\\\\ 11 C 3 = \frac{11*10*9}{3*2*1}\\\\ 11 C 3 = \frac{990}{6}\\\\ 11 C 3 = 165\\\\

We're still under our target. The good news is that the nCr value is increasing.

So the idea is to do trial and error with various values of n. Keep incrementing n until nCr = nC3 is equal to 365 or larger.

Here's a table of values where r = 3 the entire time

\begin{array}{|c|c|} \cline{1-2}\text{n} & \text{nCr}\\\cline{1-2}10 & 120\\\cline{1-2}11 & 165\\\cline{1-2}12 & 220\\\cline{1-2}13 & 286\\\cline{1-2}14 & 364\\\cline{1-2}15 & 455\\\cline{1-2}\end{array}

The nCr values are also found in Pascal's Triangle. Each of those values are the fourth entry of each row.

When n = 14, we have nCr = 364 which is very close. We're one short unfortunately.

So we have to go for <u>n = 15</u> instead. This makes the nCr value well over 365 of course, but it guarantees that you'll have plenty of trios to choose from such that no group of three is repeated. Unfortunately some trios will be left out.

7 0
2 years ago
A sledgehammer weighs 18 pounds on Earth and 4 pounds on the planet Namar. 
Advocard [28]
It would weight 18lbs i believe

8 0
3 years ago
Read 2 more answers
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Alekssandra [29.7K]
E = -5/4 or -1.25 or -1 1/4
5 0
2 years ago
Read 2 more answers
Eric paid $4.34 for peppers. Peppers cost $0.35 per pound. How many pounds of peppers did Eric buy?
n200080 [17]
Eric got 12 pounds of peppers

Hope This Helps
5 0
4 years ago
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