If they together at the same rate for the same amount of time, they will solve 48 math problems,
From the question, we can see that two mathletes solve 32 math problems in a certain amount of time, this can be written as:
- 2 mathletes = 32 math problems
In order to determine the number of problems for 3 mathletes, this is expressed as:
DIvide both expressions:
Cross multiply
2x = 3* 32
x = 3 * 16
x = 48math problems
Hence if they together at the same rate for the same amount of time, they will solve 48 math problems,
Learn more on proportion here: brainly.com/question/1496357
Answer:the answer is 9,6
Step-by-step explanation:
I JUST TOOK THE QUIZ
C is the answer
for example
assume that the height of a rectangular prism is 2, width is 1 and length measures 3
the volume will be 6
(2*1*3)
if we multiply height with the scale factor of 1/2
it becomes 1
so the volume will be 3
(1*1*3)
this situation goes for other examples, too
good luck
So 25 goes into 21 how many times? 1. Add that 1 to the 3 making 4.
Then how much is left over of the 25 & 21? 4.
Making it 4 4/21
Let's solve your system by substitution.
a=−2;b=−3
Step: Solve a=−2for a:
a=−2
Step: Substitute−2for a in b=−3:
b=−3
b=−3
Answer:
a=−2 and b=−3
