Which equation is a point slope form equation for line AB?

Bond [772]

Some other words for zero are none, not, zilch, but in the term of numbers, it would be none.

5 0

3 years ago

Hello! Happy Sunday! Got a Math question for you, anyone willing to try? Work and answer please! I think the answer is going to

NeTakaya

The length of each congruent side of the isosceles triangle is given to be equal 2.75 inches while the base calculated to be equal to 23.5 inches

<h3>How to solve for the congruent sides</h3>

We first have to define x as the length of the congruent side. The question tells us that the base is 7 inches longer than 3x the length of 2 sides

This would be represented as:

= 3(2x) + 7

= 6x + 7

The perimeter of the shape is said to be 29, hence we would have

x + x + (6x + 7) = 29

= 2x + 6x + 7 = 29

= 8x = 29 - 7

8x = 22

x = 22 / 8

= 2.75

Given the value of x we would have to put it in

6x + 7

= 6 x 2.75 + 7

= 23.5

Therefore the length of each congruent side of the isosceles triangle is given to be equal 2.75 inches while the base calculated to be equal to 23.5 inches

Read more on congruent angles here:

brainly.com/question/11949261

#SPJ1

7 0

1 year ago

In 2014, Chile experienced an intense earthquake with a magnitude of 8.2 on the Richter scale. In 2010, Haiti also experienced a

serg [7]

Answer:

The intensity of the earthquake in Chile was about 16 times the intensity of the earthquake in Haiti.

Step-by-step explanation:

Given:

magnitude of earthquake in Chile = 8.2

magnitude of earthquake in Haiti = 7.0

To find:

Compare the intensities of the two earthquakes

Solution:

The magnitude R of earthquake is measured by R = log I

R is basically the magnitude on Richter scale

I is the intensity of shock wave

For Chile:

given magnitude R of earthquake in Chile = 8.2

R = log I

8.2 = log I

We know that:

$y = log a_{x}$ is equivalent to: $x = a^{y}$

$R = log I$

8.2 = log I becomes:

$I = 10^{8.2}$

So the intensity of the earthquake in Chile:

$I_{Chile} = 10^{8.2}$

For Haiti:

R = log I

7.0 = log I

We know that:

$y = log a_{x}$ is equivalent to: $x = a^{y}$

$R = log I$

7.0 = log I becomes:

$I = 10^{7.0}$

So the intensity of the earthquake in Haiti:

$I_{Haiti} = 10^{7}$

Compare the two intensities :

$\frac{I_{Chile} }{I_{Haiti} } }$

$= \frac{10^{8.2} }{10^{7} }$

= $10^{8.2-7.0}$

= $10^{1.2}$

= 15.848932

Round to the nearest whole number:

16

Hence former earthquake was 16 times as intense as the latter earthquake.

Another way to compare intensities:

Find the ratio of the intensities i.e. $\frac{I_{Chile} }{I_{Haiti} } }$

$log I_{Chile}$ - $log I_{Haiti}$ = 8.2 - 7.0

$log(\frac{I_{Chile} }{I_{Haiti} } })$ = 1.2

Convert this logarithmic equation to an exponential equation

$log(\frac{I_{Chile} }{I_{Haiti} } })$ = 1.2

$10^{1.2}$ = $\frac{I_{Chile} }{I_{Haiti} } }$

Hence

$\frac{I_{Chile} }{I_{Haiti} } }$ = 16

6 0

3 years ago

Jerome is planning a fundraiser.

PilotLPTM [1.2K]

Answer:132

Step-by-step explanation: 1.25-.50=75 the profit of each apple is 75 cents

99 dollars divided by .75 is 132

8 0

3 years ago

Della by tree seedling that was 2 1/4 feet tall during the first year it grew 1 1/6 ft after two years it was 5 ft tall how much

jasenka [17]

<h2>Greetings!</h2>

Answer:

$\frac{19}{12}$ feet

Step-by-step explanation:

First, we need to find the height after one year:

2.25 + 1 1/6 = $\frac{41}{12}$

Now to find the amount in the second year, we can subtract the above amount from 5:

5 - $\frac{41}{12}$ = $\frac{19}{12}$

So in the second year it grew $\frac{19}{12}$ feet

<h2>Hope this helps!</h2>

8 0

3 years ago