2+1=3
15/3=5
split the 3 5's in ratio 2:1 and you get 10:5
Actually, i think something is missing here:
You need either a parenthesis or some dots at the end to determine this. A repeating decimal can have one repreating digit:
0.(7): 0.777777...
two:
0.(45): 0.45454545454545....
or more: so potentially all of them can be repeating, even a!
it could be: 1.(111114)
or: 1.111114111114111114111114111114111114111114111114111114111114111114111114111114...
proably B. is the most typical of repeating decimals (choosed this one if you have to), but in reality, you need more information... did you copy the question exactly?
Since the divisor is in the form (x + #) or (x - #), This can be done by synthetic division.
First put the polynomial ion descending order: x^2 - 7x + 15
Take the coefficients of the terms and follow these steps:
3 | 1 -7 15
3 -12
___________ Bring down the 1, multiply the 3 by the 1 and place under the
1 -4 3 -7, then add.
Multiply 3 by -4, place under the 15, then add.
The bottom row is our answer. Since the problem started with a second power, the answer will start with a first power.
The bottom row are the coefficients of the terms and the last number is the remainder.
x - 4 remainder 3 ALSO WRITTEN x - 4 + 3/(x -3)
The additive identity property states that for every number a, you have
You're showing this property when you write
