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Virty [35]
3 years ago
12

Inside a good conductor in equilibrium, such as aluminum with only small current flowing, there is almost no electric field. Thi

s is because the electrons move around and cancel out the field. What does this tell you about the electric potential inside or on the surface of a conductor
Physics
1 answer:
igomit [66]3 years ago
6 0

This means that the electric potential in the surface and inside the conductor must be constant.

<h3>What can we say about the potential on the surface of a conductor?</h3>

So in the ideal case, we can say that in a perfect conductor there is no electric field inside of it.

And we know that the electric field is given by the gradient of the electric potential, so to have no electric field inside the conductor, we must have a constant electric potential.

This means that we should have the same electric potential in the whole volume of the conductor. While in reality, this does not happen, as we actually have a small electric field inside the conductor, and this happens because there is a small change in the electric potential as we reach the surface.

If you want to learn more about electric potentials, you can read:

https://brainly.in/question/4535203

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The driver of a pickup truck accelerates from rest to a speed of 37 mi/hr over a horizontal distance of 215 ft with constant acc
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Answer:

Maximum shearing force developed in each of the two pegs during acceleration is 1830 lbf

Explanation:

First we will find the acceleration of pickup truck.

As, the acceleration is uniform, therefore we can use Newton's third equation of motion:

2as = V_{f}^{2}-V_{i}^{2}

First convert speed into ft/sec

1 mile/hr = 1.47 ft/sec

therefore,

37 mile/hr = 37 x 1.47 ft/sec

37 mile/hr =  54.39 ft/sec

with initial speed 0 ft/sec (starting from rest), using in equation of motion:

a = [(54.39 ft/sec)² - (0 ft/sec)²]/2(215 ft)

a = 6.88 ft/sec²

Now, the total shear force will be given by Newton's second law of motion:

F = ma

F = (460 lbm +72 lbm)(6.88 ft/sec²)

F = 3660 lbf

Now for the max shear force in each of the two pegs we divide total fore by 2:

Force in each peg = F/2 = (3660 lbf)/2

<u>Force in each peg = 1830 lbf</u>

4 0
4 years ago
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Yes

Explanation:

But I feel also 2 is correct but your answer is right

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