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Zepler [3.9K]
2 years ago
5

1-What is a Siphon tube used for ?

Chemistry
1 answer:
Elza [17]2 years ago
5 0

Answer:

used in irrigation to transfer water over a barrier

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Which statement is part of the kinetic molecular theory?
Tcecarenko [31]

Answer:Option A

Explanation:

4 0
3 years ago
Read 2 more answers
Please answer C...........
sergij07 [2.7K]

CH₃-CH(-CH₃)-CH(-CH₃)-CH₃

2,3-dimethyl-1-butane

Explanation:

We have the following chemical reaction:

CH₂=C(-CH₃)-CH(-CH₃)-CH₃ + H₂ → CH₃-CH(-CH₃)-CH(-CH₃)-CH₃

So 2,3-dimethyl-1-butene will react with hydrogen to produce 2,3-dimethyl-1-butane.

Learn more about:

hydrogenation of double bonds in organic compounds

brainly.com/question/5793623

brainly.com/question/4591261

#learnwithBrainly

4 0
4 years ago
PH CHEM, PLEASE HELP QUICK! NO LINKS/VIRUSES PLEASE!
Contact [7]

Answer:

The pH of the solution is 11.48.

Explanation:

The reaction between NaOH and HCl is:

NaOH  +  HCl  →  H₂O  +  NaCl

From the reaction of 3.60x10⁻³ moles of NaOH and 5.95x10⁻⁴ moles of HCl we have that all the HCl will react and some of NaOH will be leftover:

n_{NaOH}} = n_{i_{NaOH}} - n_{HCl} = 3.60 \cdot 10^{-3} moles - 5.95 \cdot 10^{-4} moles = 3.01 \cdot 10^{-3} moles

Now, we need to find the concentration of the OH⁻ ions.

[OH^{-}] = \frac{n_{NaOH}}{V}

Where V is the volume of the solution = 1.00 L                

[OH^{-}] = \frac{n_{NaOH}}{V} = \frac{3.01 \cdot 10^{-3} moles}{1.00 L} = 3.01 \cdot 10^{-3} mol/L

Finally, we can calculate the pH of the solution as follows:

pOH = -log([OH^{-}]) = -log(3.01 \cdot 10^{-3}) = 2.52

pH + pOH = 14

pH = 14 - pOH = 14 - 2.52 = 11.48

Therefore, the pH of the solution is 11.48.

I hope it helps you!

3 0
3 years ago
Hydrogen sulfate reacts with water to produce sulfate ions and hydronium ions: hso4−+h2o⇌so42−+h3o+ identify the conjugate acid-
Angelina_Jolie [31]
The generic equation for a reaction between an acid and water is 

     HX_{(aq)} + H_{2}O_{(aq)} --> X_{(aq)}^{-} + H_{3}O_{(aq)}^+

When an acid "reacts" with water, water acts as the base that accepts the proton (H+) from the acid. The remaining ion that is formed after the acid has donated its proton is called the conjugate base (X^-), and the conjugate acid-base pair is HX - X^-. 

Hydrogen sulfate (HSO_{4}^-) is an ion from sulfuric acid. It is still an acid in itself and can "react" with water ((H_{2}O) to form the sulfate (SO_{4}^2-) and hydronium (H_{3}O^+)ions. 

HSO_{4(aq)}^{-} + H_{2}O_{(aq)} --> SO_{4(aq)}^{2-} + H_{3}O_{(aq)}^+

Based on the previous discussion, SO_{4(aq)}^2- is identified to be the conjugate of the acid HSO_{4(aq)}^-. Thus, the conjugate acid-base pair is HSO_{4(aq)}^{-} - SO_{4(aq)}^{2-}.
8 0
3 years ago
All forces require an input of ______<br><br> - mass<br> - energy<br> - speed<br> - atoms
artcher [175]

Energy is the correct answer. I hope I helped you

5 0
3 years ago
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