This question is about how transformations can affect graphs.
First, we'll want to get rid of that -4 on the function of F.
So we can reflect the function over the y-axis and then compress it by a factor of 4 to make the graph 
.
Then we can move the graph over to the left 3 because the c value is positive, meaning that we move the graph over to the left.
Finally, we can move the function of by 
because the d value is positive, meaning that we move the graph up.
Hope this helps.
頑張って!
Answer:
18
Step-by-step explanation:
plug in
doo
doooo doooooooo
Step-by-step explanation:
I'm assuming you need to find the equation of that line. If that's not what you need, you can stop here, because that's what I'm going to calculate.
When we're working with the equation of a line, we know it's easy to work with if it's in the form of a "slope / intercept" equation.
That's Y = (slope) · x + (y-axis intercept)
We already know the slope of this line, because the question gave it to us. The slope is ' 8 ' . So we know the equation will be Y = 8x + (y-intercept) .
OK. We also know a point on the line ... (4, 3).
That tells us: When x=4 on this line, y=3 .
Take the equation, and put this point into it.
Y = 8x + (y-intercept)
(3) = 8(4) + y-intercept
3 = 32 + y-intercept
Subtract 32 from each side:
-29 = y-intercept
So the equation of the line is: <em>Y = 8x - 29</em>
