Answer:
Sept 6. DR Inventory (80 * 20) 1,600
CR Accounts Payable $1,600
Sept 9. DR Inventory 80
CR Cash 80
Sept 10. DR Accounts Payable 63
CR Inventory 63
Sept 12. DR Accounts Receivable (26 * 31) 806
CR Sales Revenue 806
DR Cost of Goods Sold (21 * 26) 546
CR Inventory 546
Sept 14. DR Sales Returns and Allowances 31
CR Accounts Receivable 31
DR Inventory 21
CR Cost of Goods Sold 21
Sept. 20 DR Accounts Receivable (30 * 32) 960
CR Sales Revenue 960
DR Cost of Goods Sold (30 * 21) 630
CR Inventory 630
Answer:
TOTAL 258,000
TOTAL 258,000
Explanation:
Calculation to reconcile the number of physical units Using the FIFO method
PHYSICAL UNITS
Beginning Inventory 74,000
Units Started 184,000
TOTAL 258,000
PHYSICAL UNITS
Units Completed 164,000
(258,000-94,000)
Ending Inventory 94,000
TOTAL 258,000
Therefore Using the FIFO method to reconcile the number of physical units will give us 258,000 and 258,000
<u>Answer: </u>Wrongful interference with a contractual relationship requires the existence of enforceable contract, third party knowledge, and intentional inducement.
<u>Explanation:</u>
All the business consist of information which is invaluable and wants the employees to keep it within the business and not sell it to competitors. As they are the successful objectives of the business.
Contractual relationship is the relationship bound by legal requirements where there are two or more parties who agree with same terms through enforceable contract. Intentional inducement is where an individual causes damage to contractual relationship with third party. The damage can be of monetary basis.
Answer:
The test statistic t of the sample is -0.804.
There is sufficient evidence to ascertain that the average number of years of work experience of MBA applicants is less than 3 years.
Explanation:
Null hypothesis: The average number of years of work experience of MBA applicants is 3 years.
Alternate hypothesis: The average number of yet of work experience of MBA applicants is less than 3 years.
Test statistic (t) = (sample mean - population mean) ÷ sd/√n
sample mean = 2.57
population mean = 3
sd = 3.67
n = 47
t = (2.57 - 3) ÷ 3.67/√47 = -0.43 ÷ 0.535 = -0.804
Assuming a 5% significance level
degree of freedom = n - 1 = 47 - 1 = 46
The critical value corresponding to 46 degrees of freedom and 5% significance level is 2.013.
Conclusion:
Reject the null hypothesis because the test statistic -0.804 is less than the critical value 2.013.
The years of work experience of MBA applicants is less than 3.
