3 years ago

Find the value of x. Round your answer to the nearest tenth.

Mathematics

1 answer:

Dovator [93]3 years ago

7 0

Answer:

x ≈ 36.9°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos x = $\frac{adjacent}{hypotenuse}$ = $\frac{AB}{BC}$ = $\frac{12}{15}$ , then

x = $cos^{-1}$ ( $\frac{12}{15}$ ) ≈ 36.9° ( to the nearest tenth )

You might be interested in

Draw a calendar on one sheet of paper to show each month of the year. Draw calendar so each month is given the same space what f

Elena-2011 [213]

Just draw a calendar on ur paper labeling the months

4 0

3 years ago

Ix+3l , if x>5 <br><br>+15 pts

Kaylis [27]

Cam you give the instructions???

7 0

3 years ago

Jesse and three friends buy snacks for a hike. They buy trail mix for $5.42, apples for $2.55, and granola bars for $3.99. If th

sesenic [268]

2.99 because you add the total cost up, which would be 11.96. So then you would divide 11.96 by 2.99 which gives you 2.99

8 0

3 years ago

Read 2 more answers

Si mi disco duro tiene una capacidad de 1.5 Terabytes ¿ cuántas llaves de 32 Gigabits caben en ese disco duro?

Art [367]

Answer:

The number of 32 Gigabit keys that can be fitted on the hard drive is 375.

Step-by-step explanation:

The question is:

If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?

Solution:

1 Terabyte = 8000 Gigabits

Then 1.5 Terabytes in Gigabits is:

1.5 Terabytes = (8000 × 1.5) Gigabits

= 12000 Gigabits

One key is of 32 Gigabits.

Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:

$\text{Number of 32 Gigabit keys}=\frac{12000}{32}=375$

Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.

4 0

3 years ago

If the table of the function contains exactly two potential

OverLord2011 [107]

Answer:-12<m<4

Step-by-step explanation: 2020

4 0

3 years ago