Answer:
y=2/5x+8/5
Step-by-step explanation:
so say you plot a graph of rain against the hours the gradient would be the rate of change and the information given as your points and the gradient
now to get an equation of a straight line use one of your points eg(1,2) and the gradient or rate of change mine was 0.4
Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3

Note: Negative time (-0.2) is not valid
Answer:
It's wrong because the y intercepts are different
Step-by-step explanation:
The box method is OP for these kind of questions
If I don't do a good job explaining it then I reccomend you consult the internet
x + y = 53
x -y = 9 Adding both equations
2x = 62
x = 31 y = 22