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Ivenika [448]
2 years ago
11

There are 18 students on the math team of these 5 are boys give the ratio of boys to girls on the math team in simplest form

Mathematics
2 answers:
Viefleur [7K]2 years ago
7 0

Answer:

The answer is 5/13 or 5:13

Step-by-step explanation:

There are 18 students in total. And among them there are 5 boys. You would do

18-5=13

5 boys

13 girls

Mark Brainliest Please :)

spayn [35]2 years ago
6 0

Step-by-step explanation:

  1. First subtract the number of students(18) to the number of boys(5) 18-5=13
  2. Then you can your answer in a ratio form of boy to girls the number of 5:13

Sorry if its incorrect

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Answer:

Angle M = 120 degrees

Shortest side = MN

Middle Side = MO

Longest side = ON

Step-by-step explanation:

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Amber is on a family cell phone plan with 2 other family members. The family gets 720 shared cell phone minutes a month, each fa
chubhunter [2.5K]

Amber plus 2 family members = 3 total people on the plan.

They share the minutes equally so divide the minutes by 3 to find how many she can use:

720 / 3 = 240 minutes per month.

Now divide the monthly minutes by 30 days:

240 / 30 = 8 minutes per day.

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3 years ago
Please someone help me...​
laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )}  -  \frac{1}{ \cot(6A)  -  \cot(2A) }

<u>Using trigonometric </u><u>identities</u>

That's

<h3>\cot(x)  =  \frac{1}{ \tan(x) }</h3>

<u>Rewrite the expression</u>

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )} -    \frac{1}{ \frac{1}{ \tan(6A) } }  -  \frac{1}{ \frac{1}{ \tan(2A) } }

We have

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{1}{ \frac{ \tan(2A) -  \tan(6A)  }{ \tan(6A) \tan(2A)  } }</h3>

<u>Rewrite the second fraction</u>

That's

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{ \tan(6A)  \tan(2A) }{ \tan(2A) -  \tan(6A)  }</h3>

Since they have the same denominator we can write the fraction as

-  \frac{1 +  \tan(6A) \tan(2A)  }{ \tan(2A) -  \tan(6A)  }

Using the identity

<h3>\frac{x}{y}  =  \frac{1}{ \frac{y}{x} }</h3>

<u>Rewrite the expression</u>

We have

<h3>-  \frac{1}{ \frac{ \tan(2A)  -  \tan(6A) }{1 +  \tan(6A) \tan(2A)  } }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{ \tan(x) -  \tan(y)  }{1 +  \tan(x)  \tan(y) }  =  \tan(x - y)</h3>

<u>Rewrite the expression</u>

That's

<h3>- \frac{1}{ \tan(2A -6A) }</h3>

Which is

<h3>-  \frac{1}{ \tan( - 4A) }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{1}{ \tan(x) }  =  \cot(x)</h3>

Rewrite the expression

That's

<h3>-  \cot( - 4A)</h3>

<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

<h3>- ( -  \cot(4A) )</h3>

<u>Remove the parenthesis </u>

We have the final answer as

<h2>\cot(4A)</h2>

As proven

Hope this helps you

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yKpoI14uk [10]

Answer:

Should he be surprised at this result

The found proportion is 1.56 standart deviations away from the expected. we should no be surprised .

Step-by-step explanation:

p=0,44

q=1-0.44=0.56

u=p=0,44

o=\sqrt{pq/n}=\sqrt{(0.44)(0.56)/244} = 0.032

proportion of students in binge drinking 96/244 = 0.39

The found proportion is 1.56 standart deviations away from the expected. we should no be surprised .

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