They lost -17 bc they lost -3 yards the first game and then -14 the second
Fyi don’t ever press the links it’s so they can hack u LOL
Answer:
It's A.
Step-by-step explanation:
Let's look at option A:
From the second equation y = -10 - x. Substituting in the first equation:
-10 - x = x^2 + 3x - 5
x^2 + 4x + 5 = 0
Checking the discriminant b^2 - 4ac we get 16 - 4*1*5 = -4 so there are no real roots. (A negative discriminant means no real roots).
So A has no real solution.
B.
x^2 + 3x - 5 = (20 - 4x)/5 = 4 - 0.8x
x^2 +3.8x - 9 = 0
b^2 - 4ac = (3.8)^2 - 4*1*-9 = 50.44 (positive) so there are real roots.
C.
x^2 + 3x - 5 = -9 - x
x^2 + 4x + 4 = 0
b^2 - 4ac = 4^2 - 4*1*4 = 0 so there are real roots.
Answer:
See below.
Step-by-step explanation:
(a) Because the solution led to a square root of a negative number:
x^2 -10x+40=0
x^2 - 10x = -40 Completing the square:
(x - 5)^2 - 25 = -40
(x - 5)^2 = -15
x = 5 +/-√(-15)
There is no real square root of -15.
(b) A solution was found by introducing the operator i which stands for the square root of -1.
So the solution is
= 5 +/- √(15) i.
These are called complex roots.
(c) Substituting in the original equation:
x^2 - 10 + 40:
((5 + √(-15)i)^2 - 10(5 + √(-15)i) + 40
= 25 + 10√(-15)i - 15 - 50 - 10√(-15)i + 40
= 25 - 15 - 50 + 40
= 0. So this checks out.
Now substitute 5 - √(-15)i
= 25 - 10√(-15)i - 15 - 50 + 10√(-15)i + 40
= 25 - 15 - 50 + 40
= 0. This checks out also.
