Since there are 10 pencils, and 2 erasers, the ratio of pencils to erasers is 10:2. You can divide both sides by 2 to get 5:1.
<u>First row:</u> PERCENT: 140% FRACTION: 7/5 DECIMAL: 1.4
<u>Second row:</u> PERCENT: 4% FRACTION: 1/25 DECIMAL: 0.04
<u>Third row</u>: PERCENT: 56% FRACTION:14/25 DECIMAL: 0.56
<u>Fourth row:</u> PERCENT: 95% FRACTION: 19/20 DECIMAL: 0.95
Hope this helps.
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
